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luda_lava [24]
3 years ago
8

1- O telhado de um grande galpão mede 40 m por 75 m e é feito de zinco, cujo coeficiente de dilatação térmica linear vale 3.10^-

5 oC^-1 . Ao sofrer uma elevação de temperatura de 25oC em um dia de forte calor, qual o valor da dilatação superficial do telhado? E esse aumento da área do telhado foi de um valor próximo ao da área: a) de um cartão de crédito/débito de um banco; b) de uma folha de papel sulfite; c) do tampo de uma mesa de janta; d) de uma quadra de futsal. 2 - Um cubo metálico de aresta 20 cm a 0oC, após um aquecimento uniforme, tem sua temperatura elevada em 500oC e a medida da sua aresta aumenta em 1% . Com essas informações, determine: a) a dilatação volumétrica, em cm3, sofrida pelo cubo; b) o coeficiente de dilatação volumétrico do material do cubo; c) o coeficiente de dilatação térmica linear do material do cubo.
Physics
1 answer:
Minchanka [31]3 years ago
7 0

Answer:q

Explanation:

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Answer:

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Explanation:

Use Newton's Second Law to determine the acceleration that each object has.

  • F = ma

The force applied in both cases is 50 N, but the mass for object C and object D is different.

Let's start with object C first:

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The acceleration object C undergoes is 5 m/s².  

Now let's calculate object D next:

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Object D has greater acceleration because it has a smaller mass. The object with a smaller mass will accelerate more in order to satisfy Newton's 2nd Law.

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Helium gas is compressed by an adiabatic compressor from an initial state of 14 psia and 50°F to a final temperature of 320°F in
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Answer:

The value is  P_2 = 40.54 \ psla

Explanation:

From the question we are told that

 The initial pressure is  P_1 = 14\  psla

  The initial temperature is  T_1 =  50 \ F = (50 - 32) * [\frac{5}{9} ] + 273 = 283  \  K

   The final temperature is  T_2 =  320 \ F = (320 - 32) * [\frac{5}{9} ] + 273 =433  \  K

Generally the equation for adiabatic process is mathematically represented as

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Generally for a monoatomic gas  \gamma =  \frac{5}{3}

So

           14 * 283^{\frac{\frac{5}{3} }{1- [\frac{5}{3} ]} } =P_2 * 433^{\frac{\frac{5}{3} }{1- [\frac{5}{3} ]} }

=>       14 * 283^{-2.5} =P_2 * 433^{-2.5}

=>       P_2 = 40.54 \ psla

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Answer:

the 4th one

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