What is the mass of a bullet moving at 970m/s if the bullet’s KE is 3.9x 10^3J

Physics

2 answers:

xxMikexx [17]3 years ago

7 0

I think the Answer is 0.08kg

motikmotik3 years ago

4 0

Answer:

0.08kg

Explanation:

K.E = 1/2 mv^2

v = 970m/s

K.E = 3.9x 10^3J= 3900J

K.E = 1/2 mv^2

3900 = 1/2 m x 970x 970

3900 = 1/2 ×940900m

3900 = 470450m

m = 3900/470450 = 0.00828993516 = 0.008kg

You might be interested in

An ant travels 2.78 cm [W] and then turns and travels 6.25 cm [S 40 degrees E]. What is the ant's total displacement?

Sunny_sXe [5.5K]

Answer is 6.84 approx
reason:-
(2.78^2+6.25^2)^1/2=6.84 approx

4 0

3 years ago

Explain at least 3 primary and secondary online sources of data<br>

Slav-nsk [51]

Answer And Explanation:

Primary sources of online data could be blog posts, twitter posts, and vlogs because the person producing forms of work is giving first-person account of his experience.

Secondary sources online data could be articles, news, and documentaries because people have gathered several primary sources to build their case that they are making.

Hope this is clear, and good luck with studies :)

7 0

3 years ago

Thermodynamic Processes: An ideal gas is compressed isothermally to one-third of its initial volume. The resulting pressure will

djyliett [7]

Answer:

The resulting pressure is 3 times the initial pressure.

Explanation:

The equation of state for ideal gases is described below:

$P\cdot V = n \cdot R_{u}\cdot T$ (1)

Where:

$P$ - Pressure.

$V$ - Volume.

$n$ - Molar quantity, in moles.

$R_{u}$ - Ideal gas constant.

$T$ - Temperature.

Given that ideal gas is compressed isothermally, this is, temperature remains constant, pressure is increased and volume is decreased, then we can simplify (1) into the following relationship:

$P_{1}\cdot V_{1} = P_{2}\cdot V_{2}$ (2)