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Strike441 [17]
3 years ago
12

Which process is involved in the formation of a galaxy

Physics
2 answers:
zubka84 [21]3 years ago
8 0

Answer:

SUN

Explanation:

EARTH

Tamiku [17]3 years ago
5 0
The process that is involved in the formation of the galaxy is the sun
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The period T of a simple pendulum depends on the length L of the pendulum and the acceleration of gravity g (dimensions L/P). (a
andriy [413]

Answer:

a). L= meters, g= \frac{m}{s^{2} }

b). L= 5cm  T=0.448

    L= 10 m  T=6.34

c).  Constant= \frac{2*\pi }{\sqrt{g} }=\frac{2*\pi }{\sqrt{9.8} }=2.007089923

Explanation:

a).

T= 2*\pi  \sqrt{\frac{L}{g} } = 2*\pi \sqrt{\frac{m}{\frac{m}{s^{2} } } } \\T= 2*\pi \sqrt{\frac{s^{2}*m }{m} }=2*\pi  \sqrt{s^{2}  } \\T= s

b).

L_{1}= 5 cm, 5cm *\frac{1m}{100 cm} = 0.05 m

T=2*\pi \sqrt{\frac{L}{g} }

T=2*\pi \sqrt{\frac{0.05}{9.8} }= 0.448s

L_{1}= 10 m

T=2*\pi \sqrt{\frac{L}{g} }

T=2*\pi \sqrt{\frac{10}{9.8} }= 6.43s

c).

g= 9.8 \frac{m}{s^{2} }

T=2*\pi *\frac{\sqrt{L} }{\sqrt{g} } =T=2*\pi *\frac{\sqrt{L} }{\sqrt{9.8} } \\T= 2*\pi \frac{1}{\sqrt{9.8}} *\sqrt{L}\\T= 2.007089923*\sqrt{L}

6 0
2 years ago
One of the 64.3-cm-long strings of an ordinary guitar is tuned to produce the note LaTeX: B_3B 3 (frequency 245 Hz) when vibrati
Phoenix [80]

Answer:

v = 315 m/s

Explanation:

given,

length of the string = 64.3 cm

frequency at fundamental mode = 245 Hz

speed of sound = 345 m/s

speed of the transverse waves = ?

here

wavelength = twice length of string

λ = 2 L

λ = 2 × 64.3

λ = 128.6 cm = 1.286 m

using formula

v = ν λ

v = 245 × 1.286

v = 315.07 m/s

Hence, the speed of the transverse wave on the string will be equal to v = 315 m/s

8 0
3 years ago
A small sphere with mass 5.00.×10−7kg and charge +3.00μC is released from rest a distance of 0.400 m above a large horizontal in
julia-pushkina [17]
I will assume you are asking what the initial acceleration of the sphere is since the information provided seems to indicate that.
First we need to know Newton's Law
F=ma.  
We know the mass of the sphere and we want a so we solve to get
a=F/m.
Now we need the force on the charged sphere.  This is given by the electric field, E and the charge, Q.  The relationship is F=Q×E.  (Recall that the electric field units can be expressed in Newtons/Coulomb).
Now the electric field above a large (~infinite) sheet of charge with a known charge density σ, is given by
E = σ/(2ε0)
Plug in your values of σ, to get E, then the sphere charge Q to get F, the the mass into a = F/m to get the acceleration

6 0
3 years ago
How do you calculate a bearing angle and its equivalent angle?
denis-greek [22]

Explanation:

A bearing if an angle is measured clockwise from north direction.

e.g Below the bearing of B from A is 025. (3 figures are always given). the bearing of A from B is 205°.

4 0
2 years ago
The total distance from a house to a school to is 9.5 km. A student travels all the way from his house to the school and back to
marysya [2.9K]

Answer:

0

Explanation:

Displacement is a vector from initial to final point. Because initial and final point are the same, so displacement is 0.

6 0
3 years ago
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