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3 years ago

I really need help I don't understand on evaluate and on 14

Physics

1 answer:

Assoli18 [71]3 years ago

4 0

Use the velocity formula
final velocity=intitial velocity+(acceleration x time)
plug the numbers into the equation
12=8+(a x 4)
a x 4=4
acceleration = 1 meter per second
Hope this helps.

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How do hydrogen bonds affect boiling points?

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2 years ago

Find the net charge of a system consisting of 6.25×10^6 electrons and 7.75×10^6 protons. Express your answer using three signifi

jok3333 [9.3K]

Answer:

2.40 x 10⁻¹³ C

Explanation:

$n_{e}$ = number of electrons = 6.25 x 10⁶

$q_{e}$ = charge on electron = - 1.6 x 10⁻¹⁹ C

$n_{p}$ = number of protons = 7.75 x 10⁶

$q_{p}$ = charge on proton = 1.6 x 10⁻¹⁹ C

Net charge is given as

Q = $n_{e}$ $q_{e}$ + $n_{p}$ $q_{p}$

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3 years ago

A town is considering building a biodiesel power plant that would burn biomass to generate electricity. Which of the following c

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Answer: it reduces dependence on fossil fuels. Disadvantage: it would emit pollution into the air.

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3 years ago

Which space mission visited the moon several times?.

Ivanshal [37]

NASA’s Apollo Mission was the ONLY mission which landed humans on the moon, which it did six times. I’m not very sure about several times, though. Hope this helped!

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2 years ago

a projectile is lunched with an initial speed of 60.0mm/s at an angle of 30.0° above the horizontal.The projectile lands on a hi

alexandr402 [8]

Answer:

52 mm/s (approximately)

Explanation:

Given:

Initial speed of the projectile is, $u=60.0\ mm/s$

Angle of projection is, $\theta=30.0\°$

Time taken to land on the hill is, $t=4\ s$

In a projectile motion, there is acceleration only in the vertical direction which is equal to acceleration due to gravity acting vertically downward. There is no acceleration in the horizontal direction.

So, the velocity in the horizontal direction always remains the same.

The horizontal component of initial velocity is given as:

$u_x=u\cos\theta\\u_x=60\times \cos(30)\\u_x=30\sqrt3\approx52\ mm/s$

Now, the velocity in the vertical direction goes on decreasing and becomes 0 at the highest point of the trajectory. So, at the highest point, only horizontal component acts.

Therefore, the projectile's velocity at the highest point of its trajectory is equal to the horizontal component of initial velocity and thus is equal to 52 mm/s.

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3 years ago