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3 years ago

I really need help I don't understand on evaluate and on 14

Physics

1 answer:

Assoli18 [71]3 years ago

4 0

Use the velocity formula
final velocity=intitial velocity+(acceleration x time)
plug the numbers into the equation
12=8+(a x 4)
a x 4=4
acceleration = 1 meter per second
Hope this helps.

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After landing on an unfamiliar planet, a space explorer constructs a simple pendulum of length 53.0 cm . The explorer finds that

larisa86 [58]

Answer:

12.4 m/s²

Explanation:

L = length of the simple pendulum = 53 cm = 0.53 m

n = Number of full swing cycles = 99.0

t = Total time taken = 128 s

T = Time period of the pendulum

g = magnitude of gravitational acceleration on the planet

Time period of the pendulum is given as

$T = \frac{t}{n}$

$T = \frac{128}{99}$

T = 1.3 sec

Time period of the pendulum is also given as

$T = 2\pi \sqrt{\frac{L}{g}}$

$1.3 = 2(3.14) \sqrt{\frac{0.53}{g}}$

g = 12.4 m/s²

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3 years ago

A diver can change his rotational inertia by drawing his arms andlegs close to his body in the tuck position. After he leaves th

NeX [460]

Answer:

3.14946 rad/s

Explanation:

$I_i$ = Intial moment of inertia

$I_f$ = Final moment of inertia

$\omega_i$ = Initial angular velocity

$\omega_f$ = Final angular velocity = $\dfrac{2}{1.33}\times 2\pi\ rad/s$

$\dfrac{I_f}{I_i}=\dfrac{1}{3}$

In this system the angular momentum is conserved

$L_i=L_f\\\Rightarrow I_i\omega_i=I_f\omega_f\\\Rightarrow \omega_i=\dfrac{I_f\omega_f}{I_i}\\\Rightarrow \omega_i=\dfrac{1\times \dfrac{2}{1.33}\times 2\pi}{3}\\\Rightarrow \omega_i=3.14946\ rad/s$

The angular velocity when the diver left the board is 3.14946 rad/s

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2 years ago

A venturi is constructed of a 10.0 cm pipe with a 2.0 cm diameter throat. Water pressure in the pipe is twice atmospheric pressu

postnew [5]

Answer:

$P_t=5066250.0696\ Pa=50\ atm$

Explanation:

Given:

diameter of pipe, $d=0.1\ m$

diameter of throat, $d_t=0.02\ m$

velocity of flow, $v=0.4\ m.s^{-1}$

Pressure in the pipe is twice the atmospheric pressure:

$P=2\times 101325=202650\ Pa$

Now the force of flow of water:

$F=P\times A$

now we find cross sectional area of the pipe:

$A=\frac{\pi.d^2}{4}$

$A=\pi \times\frac{0.1}{4}$

$A=0.007854\ m^2$

Therefore,

$F=202650\times 0.007854$

$F=1591.6094\ N$

Now the area at throat:

$A_t=\frac{\pi.d_t^2}{4}$

$A_t=\frac{\pi\times 0.02^2}{4}$

$A_t=0.000314\ m^2$

Therefore pressure at throat:

$P_t=\frac{F}{A_t}$

$P_t=\frac{1591.6094}{0.000314}$

$P_t=5066250.0696\ Pa=50\ atm$

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3 years ago

Explain what happens to the energy of a rock on the edge of a cliff as it falls from the

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Answer:

A rock sitting on the edge of a cliff. If the rock falls, the potential energy will be converted to kinetic energy, as the rock will be moving. The potential energy decreases as the kinetic energy increases. The potential energy decreases as the kinetic energy decreases.

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2 years ago

What is energy at motion called

salantis [7]

Energy at motion is: Kinetic energy

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3 years ago

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