Answer and Explanation:
The primitive atmosphere of Earth may have favored the abiotic synthesis of organic molecules because it **had close to no oxygen, hence, it was powerfully reducing. It had pure energy sources too in form of ultraviolet rays from the sun (it was extremely hot! Too hot for water in liquid form to exist in fact!), outgassing from the numerous volcanoes and lightning**.
Abiotic synthesis means a formation reaction where the reactants are charged to become products, almost all on their own, with no catalyst especially.
So, these factors would have helped the organic molecules to form as most of what is needed to overcome the energy barrier and become products.
Answer:
Noble gases are considered as Inert because they are unreactive.
Explanation:
Seven noble elments are known to us , they are: helium, neon, argon, krypton, xenon, radon, and oganesson. Noble gases have 8 electrons in their outermost shell and hence their valence shell is complete, they donot need further electrons to complete their octet so they are unreactive. Also they posses following properties.
Answer: 25.37055324733817mol
Approximately 25.371mol
Explanation: Number of moles of a substance is the mass of that substance containing the same amount of fundamental units, for instance atom in 12.0g of 12°C
Therefore:
Number of moles= mass/ molecular mass
Where mass of fluorine given= 482g
Standard Molecular mass of fluorine= 18.9984032g/mol
Substituting value in equation
Mole= 482g/18.9984032g/mol = 25.37055324733817mol
Approximately : 25.371mol
I think it is d it is definitely not a or b
Answer:
The answer to your question is below
Explanation:
For the reaction N2 + 3H2 = 2NH3, if you have 2.00 moles of N2 and 4.00 moles of H2 : a. Identify the limiting reactant. ____________
N2 + 3H2 = 2NH3
1 mol 3 moles 2 moles
Given 2 moles 4 moles
Rule of three for N2
x = (2 x 3) / 1 = 6 mol of H2, it means that is needed 6 moles of H2 and there are only 4, so the limiting reactant is H2
b. How many moles of NH3 can be formed? ____________
rule of three
3 moles of H2 --------------------- 2 moles of NH3
4 moles of H2 --------------------- x
x = (4x2)/3 = 2.7 moles of NH3 are formed
c. How many moles of the excess reactant will remain? _________
x = (4 x 1) / 3 = 1.33
Excess reactant = 2 - 1.33 = 0.67 moles
