Answer:
100 m/s
Explanation:
Mass the mass of Bond's boat is m₁. His enemy's boat is twice the mass of Bond's i.e. m₂ = 2 m₁
Initial speed of Bond's boat is 0 as it won't start and remains stationary in the water. The initial speed of enemy's boat is 50 m/s. After the collision, enemy boat is completely stationary. Let v₁ is speed of bond's boat.
It is the concept of the conservation of momentum. It remains conserved. So,

Putting all the values, we get :

So, Bond's boat is moving with a speed of 100 m/s after the collision.
Answer:
Work done by friction force= change in total Energy
so,
W= (friction force)*d= (mu*N)*(35)
so,
mu*m*g*35= 1/2*m*v^2
so,
mu= 0.5*(25.7)^2/(9.81*35)
solving it,
mu = 0.9618
Explanation:
Answer:
<u><em>The plank moves 0.2m from it's original position</em></u>
Explanation:
we can do this question from the constraints that ,
- the wheel and the axle have the same angular speed or velocity
- the speed of the plank is equal to the speed of the axle at the topmost point .
thus ,
<em>since the wheel is pure rolling or not slipping,</em>
<em>⇒
</em>
where
<em>
- speed of the wheel</em>
<em>
- angular speed of the wheel</em>
<em>
- radius of the wheel</em>
<em>since the wheel traverses 1 m let's say in time '
' ,</em>
<em>
</em>
∴
⇒
the speed at the topmost point of the axle is :
⇒
this is the speed of the plank too.
thus the distance covered by plank in time '
' is ,
⇒
Answer:
1. 150C.
2. 50sec
3.1.5a
Explanation:
1. I = Q/T
Q= 30x5
=150c
2.applying the formulae, I = Q/T
T= Q/I
=500/10
=50sec.
3. using the formulae i=q/t
i= 120/80
=1.5a.
Answer:
velocity of the car is 7.3516 m/s
Explanation:
M1v1a + m2v1b = m1v2a + m2v2b
775*30 + 1475*0 = 775*v2a+1475*11.9
Let v2a be x
23250 + 0 = 775x + 17552.5
775x = 23250-17552.5
775x = 5697.5
X = 7.3516 m/s