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3 years ago

What is the concentration of lithium ions in 0.390 M Li3PO4?

Chemistry

1 answer:

dolphi86 [110]3 years ago

3 0

Answer:

1.17 M

Explanation:

Step 1: Given data

Molar concentration of Li₃PO₄: 0.390 M

Step 2: Write the reaction for the dissociation of Li₃PO₄

Lithium phosphate is a strong electrolyte that dissociates according to the following equation:

Li₃PO₄(aq) ⇒ 3 Li⁺(aq) + PO₄³⁻(aq)

Step 3: Calculate the molar concentration of lithium ions

The molar ratio of Li₃PO₄ to Li⁺ is 1:3. The molar concentration of Li⁺ is 3/1 × 0.390 M = 1.17 M.

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Hydrogen 3 has a half life of 12.32 years a sample of h-3 weighing 3.02 grams is left for 15.0 years what will the final weight

yawa3891 [41]

Answer:

The final mass of sample is 1.3 g.

Explanation:

Given data:

Half life of H-3 = 12.32 years

Amount left for 15.0 years = 3.02 g

Final amount = ?

Solution:

First all we will calculate the decay constant.

t₁/₂ = ln² /k

t₁/₂ =12.32 years

12.32 y = ln² /k

k = ln²/12.32 y

k = 0.05626 y⁻¹

Now we will find the original amount:

ln (A°/A) = Kt

ln (3.02 g/ A) = 0.05626 y⁻¹ × 15.0 y

ln (3.02 g/ A) = 0.8439

3.02 g/ A = e⁰°⁸⁴³⁹

3.02 g/ A = 2.33

A = 3.02 g/ 2.33

A = 1.3 g

The final mass of sample is 1.3 g.

8 0

3 years ago

Read 2 more answers

The question is in the picture below

Rus_ich [418]

Answer:

$\Delta\text{H}_1+2\Delta\text{H}_2-\Delta\text{H}_3$

Explanation:

Hess's Law of Constant Heat Summation states that if a chemical equation can be written as the sum of several other chemical equations, the enthalpy change of the first chemical equation is equal to the sum of the enthalpy changes of the other chemical equations. Thus, the reaction that involves the conversion of reactant A to B, for example, has the same enthalpy change even if you convert A to C, before converting it to B. Regardless of how many steps it takes for the reactant to be converted to the product, the enthalpy change of the overall reaction is constant.

With Hess's Law in mind, let's see how A can be converted to 2C +E.

$\bf{\text{A} \rightarrow 2\text{B}}$ (Δ $\text{H}_1$ ) -----(1)

Since we have 2B, multiply the whole of II. by 2:

$\bf{2\text{B} \rightarrow 2\text{C} +2\text{D}}$ (2Δ $\text{H}_2$ ) -----(2)

This step converts all the B intermediates to 2C +2D. This means that the overall reaction at this stage is $\text{A} \rightarrow 2\text{C} +2\text{D}$ .

Reversing III. gives us a negative enthalpy change as such:

$\bf{2\text{D} \rightarrow \text{E}}$ (-Δ $\text{H}_3$ ) -----(3)

This step converts all the D intermediates formed from step (2) to E. This results in the overall equation of $\text{A} \rightarrow 2\text{C} +\text{E}$ , which is also the equation of interest.

Adding all three together:

$\text{A} \rightarrow 2\text{C}+\text{E}$ ( $\bf{\Delta\text{H}_1+2\Delta\text{H}_2-\Delta\text{H}_3 }$ )

Thus, the first option is the correct answer.

Supplementary:

To learn more about Hess's Law, do check out: brainly.com/question/26491956

4 0

1 year ago

H-C C-H name of formula

Vanyuwa [196]

Answer:

Ethyne

Explanation:

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3 years ago

Which of the following are balanced equations? Check all that apply.

EleoNora [17]

Answer: the answer is b

Explanation:

because why not

8 0

2 years ago

You have 180 g of radium that takes up 36 cm ^ 3 of space if you were to cut it in half and have only 90 g

Leno4ka [110]

If you were to cut the radium in half and have only 90 g, it will take up 18 cm³.

<h3>What is density?</h3>

The density of an object is the ratio of mass to volume of object.

Density = mass/volume

volume = mass/density

at a constant density, the volume of an object is proportional to its mass.

From the question, you have 180 g of radium that takes up 36 cm ^ 3 of space if you were to cut it in half and have only 90 g, the new mass will take the following volume.

180 g = 36 cm³

90 g = ?

= (90 x 36) / 180

= 18 cm³

Thus, if you were to cut the radium in half and have only 90 g, it will take up 18 cm³.

Learn more about radium here: brainly.com/question/23781489

#SPJ1

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1 year ago