Question

What is the final volume of a balloon that was initially 500.0 mL at 25°C and was then heated to 50°C?

Answer 1

Answer:

V₂  =541.94 m L.

Explanation:

Given that

V₁ = 500 mL  

T₁ = 25°C  = 273 + 25 = 298 K

T₂ = 5°C = 273+50 =323  K

The final volume = V₂  

We know that ,the ideal gas equation  

If the pressure of the gas is constant ,then we can say that

$\dfrac{V_2}{V_1}=\dfrac{T_2}{T_1}$

$\dfrac{V_2}{V_1}=\dfrac{T_2}{T_1}$

Now by putting the values in the above equation we get

$V_2=500\times \dfrac{323}{298}\ mL\\V_2=541.94\ mL$

The final volume of the balloon will be 541.94 m L.

V₂  =541.94 m L.