The individual directions of motion of Chirpy and Milada are components of projectile motion. A projectile motion is characterized by a motion in the shape of an arc. The thing about projectile motion is, the horizontal component and the vertical component are independent of each other. The horizontal motion acts on constant velocity, while the vertical motion acts on a constant acceleration equal to the force of gravity, 9.81 m/s². Even though they are independent, there is a relationship between them called the trajectory of a projectile equation:
y = xtanθ + gx²/2v²cos²θ
where
y is the vertical height
x is the horizontal range
θ is the angle of inclination
g is 9.81 m/s²
v is the initial velocity
Since Milada jumps horizontally, there is no angle of inclination: θ=0°. The initial velocity is equal to 95 cm/s or 0.95 m/s. Now, we have to determine x. But we can't do that without finding y first. This can be obtained from Chirpy's downward motion. In a free falling motion, the time of flight is equal to
t = √2y/g
2.70 = √2y/9.81
y = 35.757 m
Now, we can solve for x. I suggest you use your scientific calculator so that you can easily solve for x.
35.757 = xtan0° + (9.81)x²/2(0.95)²cos²0°
x = 2.565
Therefore, Melinda hits the ground 2.565 meters away from the base of the cliff.
Answer:
When a force acts on an object over a distance, it is said to have done work on the object. Physically, the work done on an object is the change in kinetic energy that that object experiences.
Explanation:
google lol
Answer:
<h2>6000 J</h2>
Explanation:
The work done by an object can be found by using the formula
workdone = force × distance
From the question we have
workdone = 300 × 20
We have the final answer as
<h3>6000 J</h3>
Hope this helps you
Answer:
Explanation:
Spilling the force of 60N on the rope at an angle θ in x-y direction:
fx = Fcosθ = 60cosθ
fy = Fsinθ = 60sinθ
cosθ and sinθ both vary from 0 to 1 between 0° to 90° but they go in opposite direction:
cos0° = 1 and cos90° = 0
sin0° = 0 and sin90° = 1
sin45° = cos45° = 0.7071
When θ increases from 0° to 90°,
θ=0°, fx = 60cos0° = 60N, fy = 60sin0° = 0N
θ=90°, fx = 60cos90° = 0N, fy = 60sin90° = 60N
θ=45°, fx = 60cos45° = fy = 60sin45° = 42.43N