Your closes answer would be a.10
Answer: After 4710 seconds, 1/8 of the compound will be left
Explanation:
Using the formulae
Nt/No = (1/2)^t/t1/2
Where
N= amount of the compound present at time t
No= amount of compound present at time t=0
t= time taken for N molecules of the compound to remain = 4710 seconds
t1/2 = half-life of compound = 1570 seconds
Plugging in the values, we have
Nt/No = (1/2)^(4710s/1570s)
Nt/No = (1/2)^3
Nt/No= 1/8
Therefore after 4710 seconds, 1/8 molecules of the compound will be left
It would emit energy in most of the cases in form of light
1s2 2s2 2p1
fifth electron is in 2p orbital
so answer is 2 2 -1 -1/2 , or 2 2 -1 1/2
*1/2 and -1/2 are spins, so they are interchangeable when writing the first electron in the ml