Answer:
Therefore the ratio of diameter of the copper to that of the tungsten is
Explanation:
Resistance: Resistance is defined to the ratio of voltage to the electricity.
The resistance of a wire is
- directly proportional to its length i.e
- inversely proportional to its cross section area i.e
Therefore
ρ is the resistivity.
The unit of resistance is ohm (Ω).
The resistivity of copper(ρ₁) is 1.68×10⁻⁸ ohm-m
The resistivity of tungsten(ρ₂) is 5.6×10⁻⁸ ohm-m
For copper:
......(1)
Again for tungsten:
........(2)
Given that and
Dividing the equation (1) and (2)
[since and ]
Therefore the ratio of diameter of the copper to that of the tungsten is
Momentum is the product of mass x velocity.
p = mv
Where: p = momentum
m = mass
v = velocity
Now you can answer your question by finding the momentum of each:
p = mv
p(w) = 12 x 5 = 60
p(x) = 15 x 8 = 120
p(y) = 18 x 2 = 36
p(z) = 28 x 10 = 280
With that you can now arrange them in ascending order (least to greatest):
Y < W < X < Z
Your answer is D.
Answer:
A. Increases is the answer.
Answer:
it just pulls them at the same time
Explanation: