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2 years ago

Part A Which of these is exhibiting kinetic energy?

Physics

1 answer:

Rzqust [24]2 years ago

4 0

Answer:

a space station orbiting Earth

Explanation:

Kinetic energy in an object arises from the motion of the object.

$\frac {1}{2}\times m\times v^2$ is the kinetic energy of object.

(a) a person sitting on a couch while watching TV

The person is still and is not in motion and thus, do not exhibit any kinetic energy.

(b) an archer with a flexed bow

The archer hold the bow flexed. It may have a lot of potential energy but not kinetic energy as it is still.

a space station orbiting Earth

The space station is moving and is in motion and thus, exhibits kinetic energy.

The rock is on a mountain ledge . It may have a lot of potential energy but not kinetic energy as it is still.

(d) the high-energy phosphate bonds of a molecule of ATP

The bonds are still and is not in motion and thus, do not exhibit any kinetic energy.

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A car of mass M = 1000 kg traveling at 50.0 km/hour enters a banked turn covered with ice. The road is banked at an angle θ , an

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The radius of the curved road at the given condition is 54.1 m.

The given parameters:

mass of the car, m = 1000 kg
speed of the car, v = 50 km/h = 13.89 m/s
banking angle, θ = 20⁰

The normal force on the car due to banking curve is calculated as follows;

$Fcos(\theta) = mg$

The horizontal force on the car due to the banking curve is calculated as follows;

$Fsin(\theta) = \frac{mv^2}{r}$

Divide the second equation by the first;

$\frac{Fsin(\theta)}{Fcos(\theta) } = \frac{mv^2}{rmg} \\\\tan(\theta) = \frac{v^2}{rg} \\\\r = \frac{v^2}{g \times tan(\theta)} \\\\r = \frac{13.89^2}{9.8 \times tan(20)} \\\\r = 54.1 \ m$

Thus, the radius of the curved road at the given condition is 54.1 m.

Learn more about banking angle here: brainly.com/question/8169892

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A student is on a skateboard facing a wall. The student and skateboard have a mass of 75 kilograms. The student pushes off of th

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Answer:

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The critical angle for total internal reflection for a substance is 42.0°. what is the polarizing angle for this substance?

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For the total internal reflection of a substance, we can express the relationship between the critical angle, $\theta_{c}$ , and the indices of refraction as

$n_{1} sin(\theta_{c}) = n_{2}$ (1) 

where $n_{1}$ and $n_{2}$ are the indices of refraction. And under polarization, we can express Snell's Law as

$n_{1} sin(\theta_{p}) = n_{2}sin(90-\theta_{p})$

Rearranging this we have

$n_{1} sin(\theta_{p}) = n_{2}cos(\theta_{p})$
$\frac{sin(\theta_{p}}{cos(\theta_{p})} = \frac{n_{2}}{n_{1}}$
$tan(\theta_{p}) = \frac{n_{2}}{n_{1}}$ (2)

Substituting equations (1) into (2), we have

$tan(\theta_{p}) = \frac{n_{1} sin(\theta_{c})}{n_{1}}$
$tan(\theta_{p}) = sin(\theta_{c})$

Substituting the value of the critical angle, we have

$tan(\theta_{p}) = sin(42)$
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