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3 years ago

Part A Which of these is exhibiting kinetic energy?

Physics

1 answer:

Rzqust [24]3 years ago

4 0

Answer:

a space station orbiting Earth

Explanation:

Kinetic energy in an object arises from the motion of the object.

$\frac {1}{2}\times m\times v^2$ is the kinetic energy of object.

(a) a person sitting on a couch while watching TV

The person is still and is not in motion and thus, do not exhibit any kinetic energy.

(b) an archer with a flexed bow

The archer hold the bow flexed. It may have a lot of potential energy but not kinetic energy as it is still.

<u>a space station orbiting Earth</u>

<u>The space station is moving and is in motion and thus, exhibits kinetic energy.</u>

The rock is on a mountain ledge . It may have a lot of potential energy but not kinetic energy as it is still.

(d) the high-energy phosphate bonds of a molecule of ATP

The bonds are still and is not in motion and thus, do not exhibit any kinetic energy.

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Velocity of a Hot-Air Balloon A hot-air balloon rises vertically from the ground so that its height after t sec is given by the

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Answer:

Explanation:

Given the height reached by a balloon after t sec modeled by the equation

h=1/2t²+1/2t

a) To calculate the height of the balloon after 40 secs we will substitute t = 40 into the modeled equation and calculate the value of t

If h(t)=1/2t²+1/2t

h(40) = 1/2(40)²+1/2 (40)

h(40) = 1600/2 + 40/2

h(40) = 800 + 20

h(40) = 820 feet

The height of the balloon after 40 secs is 820 feet

b) Velocity is the change of displacement of a body with respect to time.

v = dh/dt

v(t) = 2(1/2)t²⁻¹ + 1/2

v(t) = t + 1/2

when v = 0sec

v(0) = 0 + 1/2

v(0) = 1/2 ft/sec

at v = 30secs

v(30) = 30 + 1/2

v(30) = 30 1/2 ft/sec

average velocity = v(30) - v(0)

average velocity = 30 1/2 - 1/2

average velocity of the balloon between t = 0 and t = 30 = 30 ft/sec

c) Velocity is the change of displacement of a body with respect to time.

v = dh/dt

v(t) = 2(1/2)t²⁻¹ + 1/2

v(t) = t + 1/2

The velocity of the balloon after 30secs will be;

v(30) = 30+1/2

v(30) = 30.5ft/sec

The velocity of the balloon after 30 secs is 30.5 feet/sec

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3 years ago

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Answer:

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Explanation:

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3 years ago