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vladimir2022 [97]
3 years ago
13

A beaker contains a 25 ml solution of an unknown monoprotic acid that reacts in a 1:1 stoichiometric ratio with naoh. titrate th

e solution with naoh to determine the concentration of the acid. perform a titration by setting the concentration of the naoh solution and adding it to the acid solution using the different add base buttons. the equivalence point of the titration is passed when the solution color changes. the unknown sample can be titrated multiple times by pressing the retitrate button and starting over. enter the concentration of the unknown acid solution.
Chemistry
1 answer:
yuradex [85]3 years ago
5 0

<u>Given:</u>

Volume of the unknown monoprotic acid (HA) = 25 ml

<u>To determine: </u>

The concentration of the acid HA

<u>Explanation:</u>

The titration reaction can be represented as-

HA + NaOH → Na⁺A⁻ + H₂O

As per stoichiometry: 1 mole of HA reacts with 1 mole of NaOH

At equivalence point-

moles of HA = moles of NaOH

For a known concentration and volume of added NaOH we have:

moles of NaOH = M(NaOH) * V(NaOH)

Thus, the concentration of the unknown 25 ml (0.025 L) of HA would be-

Molarity of HA = moles of HA/Vol of HA

Molarity of HA = M(NaOH)*V(NaOH)/0.025 L


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