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Mashcka [7]
3 years ago
5

HEEEEELLLLLPPPPP!!!!!!!?!?!?!????!

Physics
2 answers:
mojhsa [17]3 years ago
7 0
It tells you that a star spectrum tells what atoms make up the star

lesya [120]3 years ago
5 0
B. A star's emissioin spectrum tell what atoms make up the star.

hope this helps :)

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Airborne objects tend to curve to the right
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Airborne objects tend to turn right in the northern hemisphere, caused by the Coriolis force.
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Which one of the following is NOT considered a part of a forensic scientist's job?
ki77a [65]
I see no multiple choice answer
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How were the fossil symbols and mountain bets helpful in deciding where to move the continenets
Alborosie
<span>Similar fossils found on different continents helped geologists determine how the continents used to be connected. Mountain belts marked the boundaries of moving plates, which showed in which direction the different continents drifted. Extrapolating from this information, scientists had a rough idea of how the continents were arranged eons ago.</span>
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The thermal transfer of energy by electromagnetic waves through the vacuum of space is called
Olenka [21]

Answer: Radiation

Explanation:

There are three ways in which the thermal transfer occurs:

   1. By Conduction, when the transmission is by the <u>direct contact</u>.

  2. By Convection, heat transfer <u>in fluids </u>(like water or the air, for example).  

   3. By Radiation, by the <u>electromagnetic waves</u> (they can travel through any medium and in <u>vacumm</u>)

So, in the outter space is vacuum, this means the energy cannot be transmitted by convection, nor conduction. It must be transmitted by electromagnetic waves that are able to travel with or without a medium, and this is called radiation.

4 0
2 years ago
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What would be the magnitude of the electric field 0.75 m from a 0.63 C master charge and what would be the force on a 0.50 C tes
bagirrra123 [75]

The magnitude of the electric field on the master charge is 1.008 x 10¹⁰ N/C, and the force on the test charge is 5.04 x 10⁹ N.

<h3>Electric field on the master charge</h3>

E = kq/r²

where;

  • q is magnitude of master charge
  • r is distance of separation
  • k is Coulomb's constant

E = (9 x 10⁹ x 0.63)/(0.75²)

E = 1.008 x 10¹⁰ N/C

<h3>Force on the test charge</h3>

F = Eq

where;

  • E is electric field
  • q is the test charge

F = (1.008 x 10¹⁰) x (0.5)

F = 5.04 x 10⁹ N

Thus, the magnitude of the electric field on the master charge is 1.008 x 10¹⁰ N/C, and the force on the test charge is 5.04 x 10⁹ N.

Learn more about electric field here: brainly.com/question/14372859

#SPJ1

8 0
1 year ago
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