All categories

4 years ago

If an ice cube melts at 0°C, but water also freezes at 0°C,

1 answer:

3 0

The air heat melts the ice cube due to a different change in the temperature so the ice cube will stay the same at 0•C it’s just gonna melt because of the temperature change

You might be interested in

A vacuum gage attached to a power plant condenser gives a reading of 27.86 in. of mercury. The surrounding atmospheric pressure

Nadusha1986 [10]

Answer:

absolute pressure = 1.07 lbft/in^2

Explanation:

given data:

vaccum gauge reading h = 27.86 inch = 2.32 ft

we know that

gauge pressure p is given as

$p = \rho gh$

$p = 848 \ lb/ft^3 * 32 \ ft/s^2 *2.32 ft = 62955.52 \ lbft/s^2 * 1/ft^2$

we know that $1\ lb ft\s^2 = \frac{1}{32.174}\ lbft$

1 ft = 12 inch

therefore $p = 62955.52 * \frac{1}{32.174} * \frac{1}{12^2}\ lbf/in^2$

$p = 13.59\ lbft/in^2$

$P_{atm} = 14.66\ lbf/in^2$

so absolute pressure = $P_{atm} - p$

= 14.66 - 13.59 = 1.07 lbft/in^2

4 0

3 years ago

Which condition must exist in order for conduction to occur between two substances?

kicyunya [14]

The two substances must be in contact with each other.

4 0

3 years ago

Read 2 more answers

The mass of an object is 4G and it has a density of 5gm^-3. what is the volume

tresset_1 [31]

Explanation:

Density is mass in grams over volume in cubic centimeters.

So it is

$\frac{4g}{5cm^{-3} }$ = 0.8 g/cm $^{3}$

The unit is grams per cubic centimeter.

NB - density can also be kilograms over cubic meters

3 0

3 years ago

Wat does gas mean in science

irinina [24]

Basically its just an air like fluid with chemicals.... just like air it just goes as it pleases and fills space

6 0

3 years ago

Read 2 more answers

A spring-loaded gun has a spring for which

e-lub [12.9K]

Answer:

7.5 m

Explanation:

k = Spring constant = 180 N/m

x = Displacement of spring = 14 cm

m = Mass of projectile = 0.024 kg

a = g = Acceleration due to gravity = $9.81\ \text{m/s}^2$

s = Displacement of projectile

v = Final velocity = 0

u = Initial velocity

The potential energy of the spring will be equal to the kinetic energy of the object

$\dfrac{1}{2}kx^2=\dfrac{1}{2}mu^2\\\Rightarrow u=\sqrt{\dfrac{kx^2}{m}}\\\Rightarrow u=\sqrt{\dfrac{180\times 0.14^2}{0.024}}\\\Rightarrow u=12.12\ \text{m/s}$

$v^2-u^2=2as\\\Rightarrow s=\dfrac{v^2-u^2}{2a}\\\Rightarrow s=\dfrac{0-12.12^2}{2\times -9.81}\\\Rightarrow s=7.5\ \text{m}$

The maximum height reached above the initial position is 7.5 m

5 0

3 years ago