Answer:
0.13 g
Explanation:
mass of aluminum required = ( Dislocation length) / ( Dislocation density) × (density of metal)
3000 miles to cm ( 1 mile = 160934 cm) = 3000 miles × 160934 cm / 1 mile = 482802000 cm
density of Aluminium = 2.7 g /cm³
dislocation density of aluminum = 10¹⁰ cm³
mass of aluminum required = (482802000 cm × 2.7 g/cm³) / 10¹⁰ cm³ = 0.13 g
Moles Ag = 68.3 g / 107.868 g/mol=0.633
The mass in a chemical reaction remains (mostly) the same.
(except for radiation/nuclear fission, in which mass gets converted into energy)
Citric acid
Ethanoic acid
Methanoic acid
Lactic acid
Answer:
1-Fluoro-4-nitrobenzene
Step-by-step explanation:
Step 1. Identify the substituents on the ring,
The groups are <em>fluoro</em> and <em>nitro</em>. They have no priority as functional groups, so the base name is <em>benzene</em>.
Step 2. Identify their relative priorities.
F and NO₂ have no functional group priority, so we list them in alphabetical order. F has <em>alphabetical priority </em>over NO₂. The name becomes <em>fluoronitrobenzene</em>.
Step 3. Number the atoms of the ring.
The C atom bearing the F is <em>C1.</em> Count around the ring, and the NO₂ group is on <em>C4</em>.
Step 4. Name the compound.
Insert the locating numbers <em>immediately in front</em> of the substituents. Use <em>hyphens</em> to join letters to numbers.
The name becomes 1-fluoro-4-nitrobenzene.