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puteri [66]
3 years ago
12

Identical cannonballs are fired with the same force, one each from four cannons having respective bore lengths of 1.0 meter, 2.0

meters, 2.5 meters and 3.0 meters. Which cannon will have the minimum impulse on the ball if the force acting on the ball increases with the length of the bore?
Physics
2 answers:
frez [133]3 years ago
7 0
OK think of it distance,The smaller the distance less momentum  is needed the Longer the distance the the longer the momentum is needed.

And The Answer Is quite easy their was no reason to be asked

Answer:1.0meter 
anzhelika [568]3 years ago
5 0

Answer:

The minimum impulse and force will be in the cannon of length 1 m.

Explanation:

Identical cannonballs are fired with the same force, one each from four cannons having bores lengths of 1 m, 2 m, 2.5 m, and 3 m. The force acting on the ball increases with the length of the bore.

We have the length of four bores, we need to study the force acting on the ball. As the force increases with the length, if we organize the bores according to the length values, we can estimate the forces. We need the minimum Force.

L1 = 1

L2 = 2

L3 = 2.5

L4 = 3

L4 > L3 > L2 > L1.

As the minimum length is L1, the force of L1 should be the minimum.

F4 > F3 > F2 > F1.

Finally, we can conclude that: The minimum impulse and force will be in the cannon of length 1 m. 

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24.70818432141\times 10^7\ atoms

Explanation:

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From the ideal gas law

PV=nRT\\\Rightarrow n=\frac{PV}{RT}

n=\frac{N}{N_A}

\frac{N}{N_A}=\frac{PV}{RT}\\\Rightarrow N=N_A\times \frac{PV}{RT}\\\Rightarrow N=\frac{1\times 10^{-7}\times 1\times 10^{-6}}{8.314\times 293.15}\times 6.022\times 10^{23}\\\Rightarrow N=24708184.32141\ atoms=24.70818432141\times 10^7\ atoms

The number of atoms is 24.70818432141\times 10^7\ atoms

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Therefore, the vapor pressure at 60.6°C is 330.89 mmHg

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