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Vinil7 [7]
3 years ago
6

Which of the following statements about the kinetic molecular theory are not correct?

Chemistry
1 answer:
Rashid [163]3 years ago
3 0

Answer:

The false statement is: (C) The average kinetic energy of the molecules is not related to the absolute temperature

Explanation:

According to the Kinetic Theory of Gases, gases are composed of <u>small fast moving particles that are in constant random motion</u>. These gaseous particles are known as molecules.

It is assumed that the mass of all the gaseous molecules is the same and the <u><em>intermolecular interactions (attractive or repulsive) are negligible</em></u>.

Also, the <em><u>total volume of all the gaseous molecules is considered to be negligible as compared to the volume of the container.</u></em>

According to this theory, <em><u>average kinetic energy (K) of the gaseous particles is directly proportional to the absolute temperature (T) of the gas, </u></em>by the equation:

K = \frac{3}{2}k_{b}T

<em>Here, </em>k_{b}<em> is the Boltzmann constant</em>

<u>Therefore, the false statement about the kinetic molecular theory is (C)</u>

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A solution of aqueous ammonium sulfate has a mass of 482 grams. Calculate the mass of ammonium sulfate in solution if the mass p
umka2103 [35]

Answer:

The answer to your question is the mass of solute = 53.5 g

Explanation:

Data

mass of solution = 482 g

mass of solute = ?

mass percent = 11.1 %

Mass percent is a unit of concentration. It measures the mass of the solute divided by the total mass of the solution

Process

1.- Write the formula

        Mass percent = mass of solute / mass of solution x 100

-Solve for mass of solute

          mass of solute = Mass percent x mass of solution / 100

2.- Substitution

          mass of solute = 11.1 x 482 / 100

3.- Simplification

          mass of solute = 5350.2 / 100

4.- Result

          mass of solute = 53.5g

6 0
3 years ago
What is the molarity of a solution that contains 122g of MgSO4 n 3.5L of solution?​
Semmy [17]

Answer:

0.29mol/L or 0.29moldm⁻³

Explanation:

Given parameters:

Mass of MgSO₄ = 122g

Volume of solution = 3.5L

Molarity is simply the concentration of substances in a solution.

Molarity = number of moles/ Volume

>>>>To calculate the Molarity of MgSO₄ we find the number of moles using the mass of MgSO₄ given.

Number of moles = mass/ molar mass

Molar mass of MgSO₄:

Atomic masses: Mg = 24g

S = 32g

O = 16g

Molar mass of MgSO₄ = [24 + 32 + (16x4)]g/mol

= (24 + 32 + 64)g/mol

= 120g/mol

Number of moles = 122/120 = 1.02mol

>>>> From the given number of moles we can evaluate the Molarity using this equation:

Molarity = number of moles/ Volume

Molarity of MgSO₄ = 1.02mol/3.5L

= 0.29mol/L

IL = 1dm³

The Molarity of MgSO₄ = 0.29moldm⁻³

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3 years ago
A) Atom is generally charge less,<br>why? ​
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Answer:

Explanation:

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