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Alexxandr [17]
3 years ago
12

Technician A says that shop air pressure usually ranges from 100–150 psi. Technician B says shop air pressure is around 300 psi.

Who is correct?
Physics
1 answer:
mr Goodwill [35]3 years ago
5 0

Answer:

technician A.

Explanation:

Commonly,  air pressure rating of standard shop air compressor's is between the range of 100 psi and 150 psi. And over the years since, the plant pressure creep's up , the level of pressure increases from 100 psi to at max 150 psi but not more than that. Therefore, in the given question technician A is correct and technician B is incorrect.

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Two positive charge spheres, the spheres are separated by 0.40 m. The charge on the first sphere is 100 microcoulombs and the
agasfer [191]

Answer: 168.75 N

Explanation:

first, let's convert microcoulombs to coulombs

q1 = 1e-4 C

q2 = 3e-5 C

r = 0.4 m

then use the equation Fe = \frac{kq_{1} q_{2}}{r^{2} }

plug in values --> F = (9e9*1e-4*3e-5)/(0.4)^2

F = 168.75 N

8 0
9 months ago
Is the friction of the pendulum (catch mechanism, support axis, etc.) a random or systematic error? Will this source of error ca
Hatshy [7]

Answer:

l these errors believe that the speed of the system is less than that calculated

Explanation:

When we carry out any measurement in addition to the magnitude, the sources of uncertainty must also be analyzed.

We can have random uncertainties, correspondin

g to momentary errors, for example early warps during medicine, parallax errors, errors in the starting and ending points of the movement; I mean every possible random error. This error is the one that is analyzed and calculated in the statistical equations

There is another source of error, the systematic ones, these are much more complicated, they can be an error in the pendulum length, friction in the pendulum movement mechanism, deformities in the support systems, this errors are not analyzed by the statistic, in general They discover by looking at the results and comparing with the tabulated or real ones.

 

tith the explanation we see that the errors described are systematic.

In general these errors believe that the speed of the system is less than that calculated

5 0
3 years ago
What is the effect of putting a ferromagnetic material inside the coil of a solenoid?
evablogger [386]
It strengthens the magnetic field.
3 0
3 years ago
Read 2 more answers
If a spring stores 5 j of energy when its compressed by 0.5 m. what is the spring constant
aliya0001 [1]

The elastic potential energy stored in a spring is given by:

E=\frac{1}{2}kx^2

where k is the spring constant, and x=0.5 is the compression of the spring. Re-arranging the formula and using E=5 J, we find the spring constant:

k=\frac{2E}{x^2}=\frac{2(5 J)}{(0.5 m)^2}=40 N/m

3 0
3 years ago
Read 2 more answers
Suppose an object moves along the y axis so that its location is yequals=​f(x)equals=xsquared2plus+x at time x​ (y is in​ meters
Volgvan

Answer:

A) The average velocity is 144 m/s.

B) The average velocity is (111 + h) m/s.

C) The instantaneous velocity is 111 m/s.

Explanation:

The position of the object is given by the following function:

y = f(x) = x² + x

A) The average velocity can be calculated as follows:

av = (f(xf) - f(x0)) / (xf - x0)

Where:

av = average velocity

f(xf) = the value of the function at x = x-final (xf)

f(x0) = the value of the function at x = x-initial (x0)

xf = x-final, final value of "x"

x0 = x-initial, initial value of "x"

Then the averge rate of change from x0 = 55 to xf =88 will be:

av = (f(88) - f(55))/(88 - 55)

f(x) = x² + x

Evaluating the function in x = 88 and x = 55:

f(88) = 88² + 88 = 7832 m

f(55) = 55² + 55 = 3080 m

Then:

av = 7832 m - 3080 m / (88 s - 55 s) =<u> 144 m/s</u>

B) av = (f(55 + h) - f(55)) / (55 + h - 55)

Evaluating the function in x = 55 +h:

f(55+h) = (55+h)² + (55+h)

f(55+h) = (55+h) · (55+h) + (55 + h)

f(55+h) = 55² + 55h +55h + h² + 55 +h

Evaluating the function in x = 55

f(55) = 55² + 55

Then f(xf) - f(x0):

f(55+h) - f(55) = 55² + 55h +55h + h² + 55 +h - 55² - 55

f(55+h) - f(55) = h(111 + h)

Then:

av =  h(111 + h) / h = (<u>111 + h) m/s</u>    (if h ≠ 0)

C) The instantaneous velocity is obtained by derivating the function and evaluating the derivative at x = 55.

Then:

f´(x) = 2x + 1

f´(55) = 2 · 55 + 1 = <u>111 m/s</u>

3 0
2 years ago
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