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dmitriy555 [2]
3 years ago
13

During which lunar phase is the moon’s near side entirely lit?

Chemistry
1 answer:
Bas_tet [7]3 years ago
5 0
<span> full moon is the best answer, but perhaps 90% lit, not entirely. The features we see on a full moon are shadows = not lit areas.</span>
You might be interested in
2 CuCl2 + 4 KI → 2 CuI + 4 KCl + I2
Margaret [11]

Answer: 6.75 moles

Explanation:

This is a simple stoichiometry proboe. that I would set up like this:

(13.5 moles CuCI2) (1 mol I2 / 2 moles CuCi2)

That means you all you have to do for this problem is divide by 2 and cancel out the unit moles CuCI2, which leaves you with 6.75 moles I2.

Hope this helps :)

7 0
3 years ago
An aqueous solution is found to be 3.64% potassium nitrate by mass, how many grams of solution should I evaporate the water from
Sidana [21]

Answer:

513.74 g of solution

Explanation:

% Mass grams are defined as the <em>grams that are dissolved in salt</em> (in this case, it would be <em>potassium nitrate</em>) <em>dissolved every 100 g of the solution</em>. Having this information, you can calculate the amount of solution that has dissolved 18.7 g of potassium nitrate, which is what we want to obtain.

The relationship is:

3.64 g of potassium nitrate _____ 100 g solution

18.7 g of potassium nitrate _____ X = 513.74 g of solution

Calculation: 18.7g x 100g / 3.64g = 513.74 g of solution

So, <em>I need 513.74 g of solution to get 18.7g of potassium nitrate by evaporating it</em>.

8 0
2 years ago
Which is an example of an organism? A. an octopus B. sand granules C. water D. the colors of a feather
denpristay [2]
A. An octopus

An organism is an individual animal, plant, or single-celled life form.

The octopus is the only living thing listed so that is why it is the example of an organism
5 0
3 years ago
Nitric oxide reacts with chlorine gas according to the reaction: 2 NO( g) + Cl2( g) ∆ 2 NOCl( g) Kp = 0.27 at 700 K A reaction m
11Alexandr11 [23.1K]

Answer:  The initial partial pressures of NO and Cl_2 is 139.4 torr.

Explanation:

The equilibrium reaction is

                           2NO(g)+Cl_2(g)\rightleftharpoons 2NOCl(g)

initially conc.         p            p                  0

At eqm.                p-2x        p-x               2x

Given: p_{NOCl}= 2x= 115torr

x=57.5 torr

The expression for equilibrium constant is :

K_p=\frac{p_{NOCl}^2}{p_{NO}^2\times p_{Cl_2}}

p_{NOCl} = 2x =115 torr

p_{NO} = (p-2x) = p-115 torr

p_{Cl_2} = (p-x)= p-57.5 torr

Now put all the given values in this expression, we get

0.27=\frac{(115)^2}{(p-115)^2\times (p-57.5)}

p=139.4torr

Therefore, the initial partial pressures of NO and Cl_2 is 139.4 torr.

8 0
3 years ago
Write the equation for cellular respiration using words and chemical formulas.
RSB [31]
Glucose+oxygen➡️ carbon dioxide+water+ATP
C6H12O6+O2+H2O+ATP.
let me hope that's help full
8 0
3 years ago
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