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dmitriy555 [2]
4 years ago
13

During which lunar phase is the moon’s near side entirely lit?

Chemistry
1 answer:
Bas_tet [7]4 years ago
5 0
<span> full moon is the best answer, but perhaps 90% lit, not entirely. The features we see on a full moon are shadows = not lit areas.</span>
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Write a balanced chemical equation for the standard formation reaction of gaseous hydrogen fluoride hf
pychu [463]
The  standard  state formation reaction  is  a  chemical  reaction  in  which one  moles  of  substance  in  its  standard state  is formed from  its constituent  element in  their  standard  state.All  the  substance must  be  in  their  most stable  state  at  100kpa  and  25  degrees  celsius.
therefore  for  HF is
1/2H2 +1/2F2 =HF
6 0
3 years ago
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Which organ detects stimuli from the environment and is part of the nervous system?
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3 years ago
The Michaelis constant for pancreatic lipase is 5 mM. At 60 C, lipase is subject to deactivation with a half-life of 8 min. Fat
Dmitriy789 [7]

Explanation:

According to the given data, we will calculate the following.

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                                       = 480 s

Rate constant for first order reaction is as follows.

         k_{d} = \frac{0.6932}{480}

                        = 1.44 \times 10^{-3}s^{-1}&#10;

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                                                = 45 mmol/L

Rate of hydrolysis V_m_{o} = 0.07 mmol/L/s

Conversion X = 0.80

Final concentration (S) = S_{o} (1 - X)

                                      = 45 (1 - 0.80)

                                      = 9 mol/m^{3}

or,                                  = 9 mmol/L

It is given that K_{m} = 5mmol/L

Therefore, time taken will be calculated as follows.

                    t = -\frac{1}{K_{d}}ln[1 - \frac{K_{d}}{V}{K_{M} ln (\frac{S_{o}}{S}) + (S_{o} - S)]

Now, putting the given values into the above formula as follows.

            t = -\frac{1}{K_{d}}ln[1 - \frac{K_{d}}{V}{K_{M} ln (\frac{S_{o}}{S}) + (S_{o} - S)]  

             = -\frac{1}{1.44 \times 10^{-3}s^{-1}}ln[1 - \frac{1.44 \times 10^{-3}s^{-1}}{0.07 mmol/L/s&#10;}{K_{M} ln (\frac{45 mmol/L&#10;}{9 mmol/L&#10;}) + (45 mmol/L - 9 mmol/L&#10;)]

              = 1642.83 s \times \frac{1 min}{60 sec}

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Therefore, we can conclude that time taken by the enzyme to hydrolyse 80% of the fat present is 27.38 min.

6 0
3 years ago
What mass of natural gas (ch4) must you burn to emit 272 kj of heat?
balandron [24]
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yaroslaw [1]

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In the region of the poles we see that the lines of magnetic induction are closer to each other, therefore, we consider that close to the poles the magnetic field is more intense.

See more about magentic field at brainly.com/question/14848188

#SPJ1

5 0
2 years ago
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