Answer: 6.75 moles
Explanation:
This is a simple stoichiometry proboe. that I would set up like this:
(13.5 moles CuCI2) (1 mol I2 / 2 moles CuCi2)
That means you all you have to do for this problem is divide by 2 and cancel out the unit moles CuCI2, which leaves you with 6.75 moles I2.
Hope this helps :)
Answer:
513.74 g of solution
Explanation:
% Mass grams are defined as the <em>grams that are dissolved in salt</em> (in this case, it would be <em>potassium nitrate</em>) <em>dissolved every 100 g of the solution</em>. Having this information, you can calculate the amount of solution that has dissolved 18.7 g of potassium nitrate, which is what we want to obtain.
The relationship is:
3.64 g of potassium nitrate _____ 100 g solution
18.7 g of potassium nitrate _____ X = 513.74 g of solution
Calculation: 18.7g x 100g / 3.64g = 513.74 g of solution
So, <em>I need 513.74 g of solution to get 18.7g of potassium nitrate by evaporating it</em>.
A. An octopus
An organism is an individual animal, plant, or single-celled life form.
The octopus is the only living thing listed so that is why it is the example of an organism
Answer: The initial partial pressures of
and
is 139.4 torr.
Explanation:
The equilibrium reaction is

initially conc. p p 0
At eqm. p-2x p-x 2x
Given: 

The expression for equilibrium constant is :

= 2x =115 torr
= (p-2x) = p-115 torr
= (p-x)= p-57.5 torr
Now put all the given values in this expression, we get


Therefore, the initial partial pressures of
and
is 139.4 torr.
Glucose+oxygen➡️ carbon dioxide+water+ATP
C6H12O6+O2+H2O+ATP.
let me hope that's help full