PH = -log([H+])
[H+] = 10^(-pH)
[H+] = 10^(-9)
[H+][OH-] = Kw
Kw = 1.0*10^-14 at 25 degrees celsius.
[OH-] = Kw/[H+] = (1.0*10^-14)/(1*10^-9) = 1.0*10^-5
The concentration of OH- ions is 1.0*10^-5 M.
The name given to these electrons are that they are valence electrons or binding electrons as these are directly involved in chemical Bonding and allow for different compounds to be made.
<span>Benzoin<span> is an organic compound with the formula PhCH(OH)C(O)Ph. It is
a hydroxy ketone attached to two phenyl groups.</span><span>
To answer your question, </span><span>the balanced oxidation-reduction reaction equation for the
oxidation of benzoin by ammonium nitrate is:
</span>2Ph-C(OH)-C(O)-Ph+NH4NO3
--> 2Ph-C(O)-C(O)-Ph + N2 + 3H2O.</span>
<span>
</span><span>I hope this helps and if you have any
further questions, please don’t hesitate to ask again.</span>
All of the questions here are pertaining to the colligative properties of a solution and the preparation of solutions. Maybe, it would be best if you understand the equations to be used in order to answer these questions.<span>
Freezing point depression or Boiling point elevation:
</span><span>ΔT = -K (m) (i)
</span>ΔT is the change in the freezing point or the boiling point not the freezing point/boiling point. Therefore, it should be added to the original value of the property of the solvent.
<span>
K is a constant called the molal freezing point depression constant and for the boiling point is the boiling point elevation constant. It is a property of the solvent.
</span><span>
m is the concentration of the solute in the solvent in terms of molality or kg solute/kg solvent.
</span><span>
i is the vant hoff factor which will represent the number of ions which the solute dissociates when in solution.</span>