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elena-s [515]
3 years ago
15

The density of pure silver is 10.5 g/cm3 at 20°C. If 5.25 g of pure silver pellets is added to a graduated cylinder containing 1

6.1 mL of water, to what volume level will the water in the cylinder rise?
Chemistry
1 answer:
iren [92.7K]3 years ago
7 0

Answer:

The correct answer is 16.6 mL

Explanation:

The density of a substance is defined as its mass per unit of volume. Thus:

density = mass/volume

So, to calculate volume: volume = mass/density

Given:

density= 10.5 g/cm³

mass= 5.25 g

We calculate the volume occupied by silver as follows:

volume= mass/density= (5.25 g)/(10.5 g/cm³)= 0.5 cm³

Moreover, we know that 1 cm³= 1 ml. So, a mass of 5.25 g of pure silver occupies a volume of 0.5 ml. If we add the mass of silver to a graduated cylinder with 16.1 mL of water, the final volume will be given by the initial volume of water plus the volume occupied by silver:

volume level = 16.1 mL + 0.5 mL = 16.6 mL

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Zinc metal reacts with hydrochloric acid to produce zinc(II) chloride and hydrogen gas. How many liters of hydrogen gas will be
AleksAgata [21]

Answer:

0.120 L of hydrogen gas will be produced

Explanation:

Step 1: Data given

Mass of zinc = 10.0 grams

Volume of hydrochloric acid = 23.8 mL

Molarity of hydrochloric acid = 0.45 M

Molar mass of zinc =65.38 g/mol

Step 2: The balanced equation

Zn + 2HCl → ZnCl2 + H2

Step 3: Calculate moles Zinc

Moles Zn = mass Zn / molar mass Zn

Moles Zn = 10.0 grams / 65.38 g/mol

Moles Zn  =  0.153 moles

Step 4: Calculate moles HCl

Moles HCl = molarity * volume

Moles HCl = 0.45 M * 0.0238 L

Moles HCl = 0.01071 moles

Step 5: Calculate limiting reactant

For 1 mol Zn, we need 2 moles HCl to produce 1 mol ZnCl2 and 1 mol H2

HCl is the limiting reactant. It will completely be consumed (0.01071 moles)

Zn is in excess. There will react 0.01071/2 = 0.005355 moles

There will remain 0.153 - 0.005355 = 0.147645 moles

Step 6: Calculate moles H2

For 1 mol Zn, we need 2 moles HCl to produce 1 mol ZnCl2 and 1 mol H2

For 0.01071 moles HCl we'll have 0.005355 moles H2

Step 7: Calculate volume H2

1 mol at STP = 22.4 L

0.005355 moles = 22.4 * 0.005355 = 0.120 L = 120 mL

0.120 L of hydrogen gas will be produced

4 0
3 years ago
Calculate the volume of this irregular solid to the nearest cubic centimeter​
EleoNora [17]

Answer:

8 cm3

Explanation:

The volume of this irregular solid will calculated as the difference between the final volume and the initial volume;

The final volume of the water and the solid is 25 ml

The initial volume of the water alone was 17 ml

The volume of the irregular solid is thus approximately;

25 - 17 = 8 ml

We then use the conversion;

1 cm3 = 1 mL

Thus the volume of the solid is 8 cm3

6 0
3 years ago
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Explain how to calculate net force.
Alisiya [41]
Force acting on the body when the body is at rest the net formals is given
6 0
3 years ago
Octane has a density of 0.703 g/ml. Calculate the mass of CO2(g) produced by burning one
STatiana [176]

The mass of CO₂ gas produced during the combustion of one gallon of octane is 8.21 kg.

The given parameters:

  • <em>Density of the octane, ρ = 0.703 g/ml</em>
  • <em>Volume of octane, v = 3.79 liters</em>

<em />

The mass of the octane burnt is calculated as follows;

m = \rho V\\\\m = 0.703 \ \frac{g}{ml} \times 3.79 \ L \ \frac{1000 \ ml}{L} \\\\m = 2,664.37 \ g

The combustion reaction of octane is given as;

2C_8H_{18} +  \ 25O_2 \ --> \ 16CO_2 \ + \ 18H_2O

From the reaction above:

228.46 g of octane -------------------> 704 g of  CO₂ gas

2,664.37 of octane --------------------> ? of CO₂ gas

= \frac{2,664.37 \times 704}{228.46} \\\\= 8,210.3 \ g\\\\= 8.21 \ kg

Thus, the mass of CO₂ gas produced during the combustion of one gallon of octane is 8.21 kg.

Learn more about combustion of organic compounds here: brainly.com/question/13272422

8 0
2 years ago
All reactions involving a change in temperature are exothermic.<br> a. True<br> b. False
diamong [38]
False. An increase in temperature is an exothermic reaction. However, when a temperature decreases this is known as an endothermic reactionz
8 0
3 years ago
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