From start:
Joule, J, calorie,
Example 1: 120 J / 4.184 = 28.68 cal
Example 2: 1200 cal * 4.184 = 5020.8 J
I think it is b. Ga, Ge, As, Se
The volume of the liquid sodium is 121.64 L
<h3>What is density? </h3>
The density of a substance is simply defined as the mass of the subtance per unit volume of the substance. Mathematically, it can be expressed as
Density = mass / volume
With the above formula, we can obtain the volume of the liquid. Details below
<h3>How to determine the volume of the sodium liquid</h3>
- Mass of liquid = 1.13×10⁵ g
- Density of liquid = 0.929 g/cm³
- Volume of liquid =?
Density = mass / volume
Thus,
Volume = mass / density
Volume of liquid = 1.13×10⁵ / 0.929
Volume of liquid = 121636.17 cm³
Divide by 1000 to express in liter
Volume of liquid = 121636.17 / 1000
Volume of liquid = 121.64 L
Learn more about density:
brainly.com/question/952755
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Plutonium<span> is </span>made<span> from U-238. Pu-239 is normally </span>created<span> in nuclear reactors by transmutation of individual atoms of one of the isotopes of uranium present in the fuel rods. Occasionally, when an atom of U-238 is exposed to neutron radiation, its nucleus will capture a neutron, changing it to U-239.</span>
Chemical formula of the glucose: C₆H₁₂O₆
We calculate the molar mass:
atomic mass (C)=12 u
atomic mass (H)=1 u
atomic mass (O)=16 u
atomic weight (C₆H₁₂O₆)=6(12 u)+12(1u)+6(16 u)=72 u+12u+96 u=180 u.
Therefore : 1 mol of glucose will be 180 g
The molar mass would be: 180 g/ mol
2) we calculate the number of moles of 1.5 g.
180 g---------------------1 mol
1.5 g---------------------- x
x=(1.5 g * 1 mol) / 180 g≈8.33*10⁻³ moles
we knows that:
1 mol = 6.022 * 10²³ particles (atoms or molecules)
3)We calculate the number of molecules:
Therefore:
1 mol-----------------------6.022*10²³ molecules of glucose
8.33*10⁻³ moles-------- x
x=(8.33*10⁻³ moles * 6.022*10²³ molecules)/1 mol≈5.0183*10²¹ molecules.
4)We calculate the number of C, H and O atoms:
A molecule of glucose have 6 atoms of C, 12 atoms of H, and 6 atoms of O,
number of atoms of C=(6 atoms/1 molecule)(5.0183*10²¹molecules)≈
3.011*10²²
number of atoms of H=(12 atoms/1 molecule)(5.0183*10²¹ molecules)≈
6.022*10²² .
number of atoms of O=(6 atoms/1 molecule)(5.0183*10²¹ molecules)≈
3.011*10²²
Answer: we have 3.011*10²² atoms of C, 6.022*10²² atoms of H, and 3.011*10²² atoms of O.
