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3 years ago

ASTRONOMY HELP :

Physics

1 answer:

sergeinik [125]3 years ago

4 0

Answer:

5: False

4: True

3: True (I think)

Explanation:

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A ball has m=10 kg and v=10 m/s. It has the same momentum as which of the following?

crimeas [40]

Answer:

Choice d. All three balls listed in choice a, b, and c have a momentum of $100\; \rm kg \cdot m \cdot s^{-1}$ each, same as that of the $10\; \rm kg$ ball moving at $10\; \rm m \cdot s^{-1}$ . Assumption: all four balls are moving in the same direction.

Explanation:

The momentum $p$ of an object is equal to the product of its mass $m$ and its velocity $v$ .

Momentum of a $10\; \rm kg$ ball moving at $10\; \rm m \cdot s^{-1}$ :

$p = m \cdot v = 10\; \rm kg \times 10\; \rm m \cdot s^{-1} = 100\; \rm kg \cdot m \cdot s^{-1}$ .

Similarly:

Momentum of the ball in choice a: $100 \; \rm kg \times 1\; \rm m \cdot s^{-1} = 100\; \rm kg \cdot m\cdot s^{-1}$ .
Momentum of the ball in choice b: $5 \; \rm kg \times 20\; \rm m \cdot s^{-1} = 100\; \rm kg \cdot m\cdot s^{-1}$ .
Momentum of the ball in choice c: $2 \; \rm kg \times 50\; \rm m \cdot s^{-1} = 100\; \rm kg \cdot m\cdot s^{-1}$ .

Hence the conclusion that these balls have the same momentum.

7 0

3 years ago

The index of refraction for red light in water is 1.331 and that for blue light is 1.340. A ray of white light enters the water

Alex Ar [27]

Answer:

(a) 47.08°

(b) 47.50°

Explanation:

Angle of incidence = 78.9°

For blue light :

Using Snell's law as:

$\frac {sin\theta_2}{sin\theta_1}=\frac {n_1}{n_2}$

Where,

Θ₁ is the angle of incidence

Θ₂ is the angle of refraction

n₂ is the refractive index for blue light which is 1.340

n₁ is the refractive index of air which is 1

So,

$\frac {sin\theta_2}{sin{78.9}^0}=\frac {1}{1.340}$

${sin\theta_2}=0.7323$

Angle of refraction for blue light = sin⁻¹ 0.7323 = 47.08°.

For red light :

Using Snell's law as:

$\frac {sin\theta_2}{sin\theta_1}=\frac {n_1}{n_2}$

Where,

Θ₁ is the angle of incidence

Θ₂ is the angle of refraction

n₂ is the refractive index for red light which is 1.331

n₁ is the refractive index of air which is 1

So,

$\frac {sin\theta_2}{sin{78.9}^0}=\frac {1}{1.331}$

${sin\theta_2}=0.7373$

Angle of refraction for red light = sin⁻¹ 0.7373 = 47.50°.

5 0

3 years ago

A ford escort needs a force of 3500N to accelerate at the rate of 4.9 m/s2. What is the mass of the car?

Verizon [17]

Answer:

714 kg

Explanation:

ΣF = ma

3500N = 4.9m/s^2*m

m ~= 714 kg

5 0

2 years ago

Two light sources can be adjusted to emit monochromatic light of any visible wavelength. The two sources are coherent, 2.04μm ap

tigry1 [53]

Answer:

Explanation:

Path difference for the observer = 2.04μm

For constructive interference

path difference = n λ

2.04μm = 5 x .408 or , 4 x .51 or 3 x .68μm

For visible wavelengths like .408 , .51 or .68 μm (400 to 700 nm) will the observer see the brightest light due to constructive interference.

B) If the two sources were not in line with the observer, but were still arranged so that one source is 2.04μm farther away from the observer than the other , in that case also , interference pattern will be visible .

c )

For destructive interference

2.04 μm = (2n+1)λ / 2

2.04μm = 3.5 x .58μm

2.04 μm = 4.5 x .45μm

So for .58μm and .45μm , destructive interference will take place

4 0

3 years ago

Convert 2m^2 to in^2 show work

nalin [4]

Explanation:

$1m \: = 39.4 \: in \\ \\ 2 {m}^{2} . \frac{39.4 \: in}{1 \: m} . \frac{39.4 \: in}{1 \: m} = 3104.7 \: {in}^{2}$

5 0

4 years ago