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Murrr4er [49]
2 years ago
10

An ecosystem includes the biotic and abiotic factorstruefalse​

Chemistry
2 answers:
MariettaO [177]2 years ago
8 0
True.

Every environment and ecosystem will include these factors.
Lyrx [107]2 years ago
7 0
True.
Every ecosystem has living and non living factors.
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What must be true about two objects if heat is flowing between them?
Katarina [22]

Answer:

The temperatures of the objects must be different

Explanation:

if heat is flowing between two objects, then the objects must be at different temperatures.

7 0
2 years ago
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What is the volume, in liters, of 2.00 moles of hydrogen at STP?
Ber [7]
The volume of one mole of any gas at STP is 22.4 L. So, at STP, the volume of 2.00 moles of hydrogen gas would be (22.4 L/mol)(2 mol H2) = 44.8 L.
8 0
3 years ago
PLEASE HELP ME BABES AND ASAP PLEASE!!
Goryan [66]
What special structures are needed for green plants?
<span> A.chloroplasts and chlorophyll

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<span> What happens during the light reaction of photosynthesis? </span>
<span> D. Water molecules split apart. (Not 100%) </span>
5 0
3 years ago
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Write the equilibrium expression for N2 (g) + 3 H2 (g) ↔ 2 NH3 (g) + heat I have no idea where to even start, due to the corona
motikmotik

Answer:

The expression of an equilibrium constant will given as:

K_c=\frac{[NH_3]^2}{[N_2][H_2]^3}

Explanation:

Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as K_{eq}

K is the constant of a certain reaction when it is in equilibrium

N_2 (g) + 3 H_2 (g)\rightleftharpoons 2 NH_3 (g) + heat

The expression of an equilibrium constant will given as:

K_c=\frac{[NH_3]^2}{[N_2][H_2]^3}

5 0
2 years ago
A pan containing 40 grams of water was allowed to cool from a temperature of 91.0C. If the amount of heat repressed is 1,300 jou
Vinvika [58]

Answer:

83°C

Explanation:

The following were obtained from the question:

M = 40g

C = 4.2J/g°C

T1 = 91°C

T2 =?

Q = 1300J

Q = MCΔT

ΔT = Q/CM

ΔT = 1300/(4.2x40)

ΔT = 8°C

But ΔT = T1 — T2 (since the reaction involves cooling)

ΔT = T1 — T2

8 = 91 — T2

Collect like terms

8 — 91 = —T2

— 83 = —T2

Multiply through by —1

T2 = 83°C

The final temperature is 83°C

3 0
3 years ago
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