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kupik [55]
3 years ago
11

Fill in the missing term in the equation. x/x^2-4x+4-x/x^2-3x+2=?/(x-2)^2(x-1)

Mathematics
2 answers:
Gnom [1K]3 years ago
8 0

Answer:

The missing term is x.

Step-by-step explanation:

Given expression is,

\frac{x}{x^2-4x+4}-\frac{x}{x^2-3x+2}------(1)

Since, x^2-4x+4=(x)^2-2\times (2x)+(2)^2

\implies x^2-4x+4=(x-2)^2------(2)    ( (a-b)² = a² - 2ab + b² )

Now,   x^2-3x+2=x^2-2x-x+2    ( By middle term splitting )

=x(x-2)-1(x-2)

\implies x^2-3x+2=(x-1)(x-2)------(3)

From equation (1), (2) and (3),

\frac{x}{x^2-4x+4}-\frac{x}{x^2-3x+2}=\frac{x}{(x-2)^2}-\frac{x}{(x-2)(x-1)}

=\frac{x(x-1)-x(x-2)}{(x-2)^2(x-1)}

=\frac{x(x-1-x+2)}{(x-2)^2(x-1)}

=\frac{x(1)}{(x-2)^2(x-1)}

=\frac{x}{(x-2)^2(x-1)}

Hence, the missing term in the equation is x.

emmainna [20.7K]3 years ago
5 0
<span>           x                            x
-----------------  -  --------------------
x^2 -4x + 4            </span><span>x^2-3x+2

</span>           x                            x
= ----------------  -  --------------------
    (x -2)^2            (x - 2)(x - 1)

        x (x-1)  - x(x +2)                       
= ----------------------------
          (x -2)^2 (x - 1)

      x^2 -x -x^2 - 2x                    
= --------------------------
      (x -2)^2 (x - 1)

           -3x                    
= -----------------------
      (x -2)^2 (x - 1)

answer 
<span>missing term in the equation: -3x</span>
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