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viktelen [127]
3 years ago
10

What is the most common injury caused by working with machines unsafely?

Engineering
2 answers:
VladimirAG [237]3 years ago
8 0

Answer:

heyooo!!!!!!

Burns and scarring.

hope this helps!!!!

Explanation:

Lena [83]3 years ago
6 0

Answer:

<u>The most common injury caused by working with machinery are cuts and burns.</u>

Explanation:

Many times when working with machinery there are certain risks of damage to the personnel who handle them, so it is correct to request protective equipment for workers.

For example, if the most common injuries are <u>cuts and burns</u>, workers are asked to wear gloves or any protective equipment that covers them to avoid these damages when handling materials.

Safety shoes, glasses, gloves, helmet, mask and hearing protectors are the most recommended for any work with machinery.

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An aquifer has three different formations. Formation A has a thickness of 8.0 m and hydraulic conductivity of 25.0 m/d. Formatio
saveliy_v [14]

Answer:

The horizontal conductivity is 41.9 m/d.

The vertical conductivity is 37.2 m/d.

Explanation:

Given that,

Thickness of A = 8.0 m

Conductivity = 25.0 m/d

Thickness of B = 2.0 m

Conductivity = 142 m/d

Thickness of C = 34 m

Conductivity = 40 m/d

We need to calculate the horizontal conductivity

Using formula of horizontal conductivity

K_{H}=\dfrac{H_{A}K_{A}+H_{A}K_{A}+H_{A}K_{A}}{H_{A}+H_{B}+H_{C}}

Put the value into the formula

K_{H}=\dfrac{8.0\times25+2,0\times142+34\times40}{8.0+2.0+34}

K_{H}=41.9\ m/d

We need to calculate the vertical conductivity

Using formula of vertical conductivity

K_{V}=\dfrac{H_{A}+H_{B}+H_{C}}{\dfrac{H_{A}}{K_{A}}+\dfrac{H_{B}}{K_{B}}+\dfrac{H_{C}}{K_{C}}}

Put the value into the formula

K_{V}=\dfrac{8.0+2.0+34}{\dfrac{8.0}{25}+\dfrac{2.0}{142}+\dfrac{34}{40}}

K_{V}=37.2\ m/d

Hence, The horizontal conductivity is 41.9 m/d.

The vertical conductivity is 37.2 m/d.

3 0
2 years ago
Calculate the molar heat capacity of a monatomic non-metallic solid at 500K which is characterized by an Einstein temperature of
aleksandr82 [10.1K]

Answer:

Explanation:

Given

Temperature of solid T=500\ K

Einstein Temperature T_E=300\ K

Heat Capacity in the Einstein model is given by

C_v=3R\left [ \frac{T_E}{T}\right ]^2\frac{e^{\frac{T_E}{T}}}{\left ( e^{\frac{T_E}{T}}-1\right )^2}

e^{\frac{3}{5}}=1.822

Substitute the values

C_v=3R\times (\frac{300}{500})^2\times (\frac{1.822}{(1.822-1)^2})

C_v=3R\times \frac{9}{25}\times \frac{1.822}{(0.822)^2}

C_v=0.97\times (3R)            

6 0
2 years ago
The Stefan-Boltzmann law can be employed to estimate the rate of radiation of energy H from a surface, as in
Mazyrski [523]

Explanation:

A.

H = Aeσ^4

Using the stefan Boltzmann law

When we differentiate

dH/dT = 4AeσT³

dH/dT = 4(0.15)(0.9)(5.67)(10^-8)(650)³

= 8.4085

Exact error = 8.4085x20

= 168.17

H(650) = 0.15(0.9)(5.67)(10^-8)(650)⁴

= 1366.376watts

B.

Verifying values

H(T+ΔT) = 0.15(0.9)(5.67)(10)^-8(670)⁴

= 1542.468

H(T+ΔT) = 0.15(0.9)(5.67)(10^-8)(630)⁴

= 1205.8104

Error = 1542.468-1205.8104/2

= 168.329

ΔT = 40

H(T+ΔT) = 0.15(0.9)(5.67)(10)^-8(690)⁴

= 1735.05

H(T-ΔT) = 0.15(0.9)(5.67)(10^-8)(610)⁴

= 1735.05-1059.83/2

= 675.22/2

= 337.61

5 0
3 years ago
What is the IMA of this pulley belt system if the diameter of the input
Stella [2.4K]

Answer:

2.8

Explanation:

The ideal mechanical advantage of the pulley IMA  = D'/D where D' = diameter of output pulley = 7 inches and D = diameter of input pulley = 2.5 inches

So, IMA = D'/D

= 7/2.5

= 2.8

So, the ideal mechanical advantage of the pulley IMA = 2.8

8 0
2 years ago
2x²-6x+10/x-2 x=2<br><br><br>plsssss<br><br><br><br>​
aleksandr82 [10.1K]

Answer:

hope it helps you..

5 0
2 years ago
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