Answer:
The question is incomplete, below is the complete question
"The real power delivered by a source to two impedance, Z1=4+j5Ω and Z2=10Ω connected in parallel, is 1000 W. Determine (a) the real power absorbed by each of the impedances and (b) the source current."
answer:
a. 615W, 384.4W
b. 17.4A
Explanation:
To determine the real power absorbed by the impedance, we need to find first the equivalent admittance for each impedance.
recall that the symbol for admittance is Y and express as
Hence for each we have,
for the second impedance we have
we also determine the voltage cross the impedance,
P=V^2(Y1 +Y2)
The real power in the impedance is calculated as
for the second impedance
b. We determine the equivalent admittance
We convert the equivalent admittance back into the polar form
the source current flows is
Answer:
True
Explanation:
Dual home host - it is referred to as the firewall that is incorporated with two or more networks. out of these two networks, one is assigned to the internal network and the other is for the network. The main purpose of the dual-homed host is to ensure that no Internet protocol traffic is induced between both the network.
The most simple example of a dual-homed host is a computing motherboard that is provided with two network interfaces.
Answer:
12
Explanation:
19-7 lol this is to easy im in middle school
The condensed Q formula may be used for operations in which the friction loss can be determined for a: 3, 4, or 5 inch hose.
<h3>What is a firehose friction loss?</h3>
A firehose friction loss can be defined as a measure of the effect of the resistance of water against the inner side of a firehose, which typically results in a pressure drop at the terminal end.
Generally, some of the factors that affect the resistance or friction in a firehose include:
Mathematically, the firehose friction loss can be calculated by using this formula:
FL = C × (Q/100)² × L/100.
Read more on friction loss here: brainly.com/question/17305262
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