Answer:
hello hi how are you glad you're good goodbye
Answer:
7.68 m
Explanation:
Kinetic energy in ball = elastic energy in spring
KE = EE
½ mv² = ½ kx²
mv² = kx²
x = v √(m / k)
x = (38.5 m/s) √(20.5 kg / 515 N/m)
x = 7.68 m
Answer:
The magnitude of the free-fall acceleration at the orbit of the Moon is 
(
, where 
).
Explanation:
According to the Newton's Law of Gravitation, free fall acceleration (
), in meters per square second, is directly proportional to the mass of the Earth (
), in kilograms, and inversely proportional to the distance from the center of the Earth (
), in meters:
(1)
Where:
- Gravitational constant, in cubic meters per kilogram-square second.
- Mass of the Earth, in kilograms.
- Distance from the center of the Earth, in meters.
If we know that 
, 
and 
, then the free-fall acceleration at the orbit of the Moon is:
Ahhh... hello! I’ve done a science experiment that has asked this sort of question. Not as easy as it sounds... I know. I’ll tell you what I learned from that experiment. The answer will depend on the materials the ball is made of and then also your drop length. After these two things are determined, you can get a pretty close time and measurement. I hope this information helps. Have a great night!
~Brooke❤️
I believe it’s c if not sorry
