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3 years ago

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A neutralization reaction between an acid and sodium hydroxide formed water and the salt named sodium sulfate. What was the form

ula of the acid that was neutralized? A neutralization reaction between an acid and sodium hydroxide formed water and the salt named sodium sulfate. What was the formula of the acid that was neutralized? H2SO4 Na2SO4 H2S HCl none of the above

1 answer:

myrzilka [38]3 years ago

3 0

Answer: The formula of the acid that was neutralized is $H_2SO_4$

Explanation:

Neutralization is a chemical reaction in which acid and base combine to form salt and water. Acids donate $H^+$ and bases donate $OH^-$ in water which combine to form water molecules.

As the salt formed is $Na_2SO_4$ , the acid must contain $SO_4$ and thus the acid is $H_2SO_4$

The balanced chemical reaction is ;

$H_2SO_4+2NaOH\rightarrow Na_2SO_4+2H_2O$

The formula of the acid that was neutralized is $H_2SO_4$

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the presidential inauguration is free to watch with or without paying ror traditional tv service. Why is this important?

sp2606 [1]

Answer:

so that people would be able to witness the inauguration of a president, since a president is an important part of a country.

Explanation:

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3 years ago

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Determine the pressure change when a volume of gas at 760 mmHg is heated from 30.0 °C to 40.0 °C.

bekas [8.4K]

Answer:

<u>253.33 mmHg</u>

Explanation:

According to Charles' Law,

P₁ / T₁ = P₂ / T₂

P₁T₂ = P₂T₁

P₂ = P₁T₂ / T₁

= 760 x 40 / 30

= 760 x 4/3

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Change in Pressure

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1 year ago

Which sample of matter has a crystal structure?

Maurinko [17]

The correct answer:C) NaCl(s)
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3 years ago

How many molecules of carbon dioxide are dissolved in 0.550 L of water at 25 °C if the pressure of CO2 above the water is 0.250

Grace [21]

<u>Answer:</u> The number of molecules of carbon dioxide gas are $2.815\times 10^{21}$

<u>Explanation:</u>

To calculate the molar solubility, we use the equation given by Henry's law, which is:

$C_{CO_2}=K_H\times p_{CO_2}$

where,

$K_H$ = Henry's constant = $0.034mol/L.atm$

$C_{CO_2}$ = molar solubility of carbon dioxide gas

$p_{CO_2}$ = pressure of carbon dioxide gas = 0.250 atm

Putting values in above equation, we get:

$C_{CO_2}=0.034mol/L.atm\times 0.250atm\\\\C_{CO_2}=8.5\times 10^{-3}M$

To calculate the number of moles for given molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$

Molarity of carbon dioxide = $8.5\times 10^{-5}M$

Volume of solution = 0.550 L

Putting values in above equation, we get:

$8.5\times 10^{-3}M=\frac{\text{Moles of }CO_2}{0.550L}\\\\\text{Moles of }CO_2=(8.5\times 10^{-3}mol/L\times 0.550L)=4.675\times 10^{-3}mol$

According to mole concept:

1 mole of a compound contains $6.022\times 10^{23}$ number of molecules

So, $4.675\times 10^{-3}$ moles of carbon dioxide will contain = $(6.022\times 10^{23}\times 4.675\times 10^{-3})=2.815\times 10^{21}$ number of molecules

Hence, the number of molecules of carbon dioxide gas are $2.815\times 10^{21}$

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2 years ago

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How many grams of FeCl 3 are in 250. mL of a 0.100 M solution?

Naddika [18.5K]

Answer:

The correct answer is option B

Explanation:

$$Molarity=\frac{Weight}{Molecular \,weight} \frac{1000}{V(in \, ml)}$

Given values,

Molarity of $FeCl_3=0.100M$

Volume of solution, $V=250ml$

Molecular weight of $FeCl_3=162.2$

Substituting this values in Molarity formula, we get

$0.1=\frac{weight}{162.2} \times\frac{1000}{250} $\\$\Rightarrow 16.22=weight\times4$\\$\Rightarrow weight=\frac{16.22}{4} $\\$\therefore weight=4.06g$

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3 years ago