Answer:

Explanation:
Acceleration is the change in velocity over time.

The object accelerates <em>from</em> 45 meters per second <em>to </em>10 meters per second in 5 seconds. Therefore,

Substitute the values into the formula.

Solve the numerator.

Divide.


The acceleration of the object is -7 meters per square second. The acceleration is negative because the object's velocity decreases and the object slows down.
Answer:
from the position of the center of the Sun
Explanation:
As we know that mass of Sun and Jupiter is given as


distance between Sun and Jupiter is given as

now let the position of Sun is origin and position of Jupiter is given at the position same as the distance between them
so we will have


from the position of the center of the Sun
Answer:
The objects outside the reference frame aren't moving. It appears this way since the vehicle you are inside is moving, but unless the objects are people, animals, or other vehicles, the objects aren't moving.
Explanation:
We'll call the radius r and the diameter d:
We also assume that the riders are at a distance r = d/2 = 7m from the center of the wheel.
The period of the wheel is 24s. The tangent velocity of the wheel (and the riders) will be: (2pi/T)*r = 0.8 m/s (circa).
It means that in 3 minutes (180 seconds) they'll run 0.8 m/s * 180s = 144m.
Hopefully I understood the question. If yes, that's the answer.
Answer:
I just toughed it out and talked with friends
Explanation: