Answer:
0.5 V
Explanation:
The electric potential distance between different locations in an electric field area is unaffected by the charge that is transferred between them. It is solely dependent on the distance. Thus, for two electrons pushed together at the same distance into the same field, the electric potential will remain at 1 V. However, the electric potential of one of the two electrons will be half the value of the electric potential for the two electrons.
Answer:
A) 580m
B) 0 m/s
C) 9.8m/s^2
D) downward
E) 10.87s
F) 106.62 m/s
Explanation:
A) The distance traveled by the rocket is calculated by using the following expression:

a: acceleration of the rocket = 2.90 m/s^2
t: time of the flight = 20.0 s

B) In the highest point the rocket has a velocity with magnitude zero v = 0m/s because there the rocket stops.
C) The engines of the rocket suddenly fails in the highest point. There, the acceleration of the rocket is due to the gravitational force, that is 9.8 m/s^2
D) The acceleration points downward
E) The time the rocket takes to return to the ground is given by:

10.87 seconds
F) The velocity just before the rocket arrives to the ground is:

Answer:
125 m
Explanation:
Given:
v₀ = 20 m/s
v = 0 m/s
a = -1.6 m/s²
Find: Δy
v² = v₀² + 2aΔy
(0 m/s)² = (20 m/s)² + 2 (-1.6 m/s²) Δy
Δy = 125 m
You know I’m going to be honest I don’t feel like it