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forsale [732]
3 years ago
3

Identify the spectator ions in the following complete ionic equation. 2k (aq) s2−(aq) pb2 (aq) 2no−3(aq)→pbs(s) 2k (aq) 2no−3(aq

) express your answers as ions separated by a comma.
Chemistry
2 answers:
zhuklara [117]3 years ago
8 0

Answer : The spectator ions are, K^+,NO_3^-

Explanation :

In the net ionic equations, we are not include the spectator ions in the equations.

Spectator ions : The ions present on reactant and product side which do not participate in a reactions. The same ions present on both the sides.

The given balanced ionic equation will be,

2K_2S(aq)+Pb(NO_3)_2(aq)\rightarrow 2KNO_3(aq)+PbS(s)

The ionic equation in separated aqueous solution will be,

2K^+(aq)+S^{2-}(aq)+Pb^{2+}(aq)+2NO^{3-}(aq)\rightarrow PbS(s)+2K^+(aq)+2NO^{3-}(aq)

In this equation, K^+\text{ and }NO_3^- are the spectator ions.

By removing the spectator ions from the balanced ionic equation, we get the net ionic equation.

The net ionic equation will be,

Pb^{2+}(aq)+S^{2-}(aq)\rightarrow PbS(s)

Feliz [49]3 years ago
7 0
The only spectator ions present are 2K, 2NO-3
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<span>Answer:
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