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Alisiya [41]
3 years ago
15

Why do we use cobalt glass for sodium and potassium

Chemistry
1 answer:
Black_prince [1.1K]3 years ago
7 0

Cobalt is a very intense glass colorant and very little is required to show a noticeable amount of color. Cobalt blue glass is also used as an optical filter in flame tests to filter out the yellow flame caused by contamination with sodium, and expand the ability to see violet and blue hues, (colors).

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why is a molecule of CO2 non polar even though the bonds between the carbon atom and the oxygen atoms are polar
stira [4]

Answer:

m

Explanation:

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2 years ago
Please help! Asap! :)
timama [110]

The first one is true.

The second one is false.

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3 years ago
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Help me with this pleaseeeeeee
stiks02 [169]

Magnesium oxide is an ionic compound with a very high melting point and which requires a large amount of energy for melting.

<h3>What are ionic compounds?</h3>

Ionic compounds are compounds which are formed between oppositely charged ions which are held together by electrostatic forces of attraction between the oppositely charged ions.

Ionic compounds are formed when metal atoms donate electrons to non-metals atoms to form ions.

Magnesium oxide is an ionic compound.

The nature of bonding is ionic bonding.

It has a crystalline lattice structure.

The forces of attraction is electrostatic forces of attraction.

It has a high melting point of 2,852 °C, and thus requires a large amount of energy go melting to occur.

Therefore, magnesium oxide is an ionic compound which requires a large amount of energy for melting.

Learn more about ionic compounds at: brainly.com/question/11638999

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2 years ago
What is rust classified as
kotykmax [81]

Rust is classified as Metal Oxide!

4 0
3 years ago
How many grams of propane are in 20 pounds of propane? Use the conversion 1 lb = 454 g. (Express your answers for the next three
Dima020 [189]

Answer:

a. =9.1x10^3gC_3H_8

b. 2.1x10^2molC_3H_8

c. Q=-4.6x10^5kJ

Explanation:

Hello,

a. By applying the given information, one obtains:

20lbC_3H_8*\frac{454gC_3H_8}{1lbC_3H_8} =9.1x10^3gC_3H_8

b. By knowing that the propane has a molecular mass of 44g/mol, one obtains:

20lbC_3H_8*\frac{454gC_3H_8}{1lbC_3H_8}*\frac{1molC_3H_8}{44gC_3H_8} =2.1x10^2molC_3H_8

c. Here, the propane's combustion chemical reaction is stated:

C_3H_8+5O_2-->3CO_2+4H_2O

This enthalpy of reaction is computed via:

ΔrH=(3*-393.5kJ/mol)+(4*241kJ/mol)-(-104.7kJ/mol)=-2043kJ/mol

Finally, since it is done for 20 lb of propane (2.1x10^2molC_3H_8), the obtainable energy is:

Q=-2043kJ/mol*2.1x10^2molC_3H_8\\Q=-4.6x10^5kJ

Best regards.

4 0
3 years ago
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