Answer:

Explanation:
Wien's displacement law states that the radiation of the black body curve for different temperatures will give peak values at different wavelengths and this wavelength is related inversely to the temperature.
Formally the law of Wien displacement states that the black body's spectral radiation per unit of wavelength, will give peaks at the wavelength of
which is given by the mathematical expression.
Here, b is proportionality constant with value of
The wavelength of the peak of the Gaussian curve is inversely related to temperature in degree kelvin.
1665183.6J
Explanation:
Given parameters:
Mass of Gold = 12400g
Initial temperature = 23°C
Final temperature = 1064°C
Unknown:
Energy required to melt = ?
Solution:
The amount of heat required to cause this temperature change to heat the gold bar is given as;
H = m c Ф
m is the mass of gold bar
c is the specific heat capacity of gold
Ф is the heat change
Specific heat capacity of gold = 0.129J/g°C
H = m c (Ф₂ - Ф₁)
H = 12400 x 0.129 x (1064 - 23) = 1665183.6J
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Newton’s Second Law
Unbalanced forces
When the forces acting on an object do not balance, the resultant force will cause the object to accelerate in the direction of the resultant force.
In other words, a resultant force on a body will cause it to change its velocity. This simply means that unbalanced forces will cause:
acceleration
deceleration
change in direction
Explanation:
Answer:
In space there is no air resistance. on earth there is
in space there is no opposite forces acting on stopping the ball, so if you throw it it will go on forever.
on earth there is air resistance and gravity, this will pull the ball towards the ground and slow it down.
Explanation:
initial height, yo = 2 m
initial velocity, u = 20 m/s
angle of projection,θ = 5 degree
distance of net = 7 m
height of net = 1 m
Let it covers a vertical distance y in time t .
Use Second equation of motion for vertical motion
As it hits the ground in time t, so put y = 0
Taking positive sign, t = 0.84 s
The ball travels a horizontal distance x in time t
X = 20 Cos5 x t
X = 16.76 m
As this distance is more than the distance of net, so it clears the net.
Let t' be the time taken to travel a horizontal distance equal to the distance of net
7 = 20 cos5 x t'
t' = 0.35 s
Let the vertical distance traveled by the ball in time t' is y'.
So,
y' = 2.008 m
So, it clears the net which is 1 m high.
It clears the net by a vertical distance of 2.008 - 1 = 1.008 m and horizontal distance 16.76 - 7 = 9.76 m
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