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ZanzabumX [31]
3 years ago
14

Consider a mixture of air and gasoline vapor in a cylinder with a piston. The original volume is 40. cm3. If the combustion of t

his mixture releases 912 J of energy, to what volume will the gases expand against a constant pressure of 635 torr if all the energy of combustion is converted into work to push back the piston?
Chemistry
1 answer:
maks197457 [2]3 years ago
8 0

Answer:

The gases will expand until a volume of Vf= 10812 cm^3

Explanation:

Since the gas mixture is expanding at constant pressure

W=\int\limits^{Vf}_{Vi} {P} \, dV =P(Vf-Vi)

and therefore

Vf=W/P+Vi

knowing that 1 torr=133,32 Pa

p=635 torr * 133,322 Pa/torr * 1m^{3}/10^{6}cm^{3}=0,08466 J/ cm^{3}

therefore

Vf=912 J/(0,08466 J/cm^{3}) +40cm^{3} =10812 cm^{3}

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35

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A more reactive metal displaces a less reactive metal from salt solution. Such reactions are called:
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Displacement Reaction.

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Diatomic iodine [I2] decomposes at high temperature to form I atoms according to the reaction I2(g)⇌2I(g), Kc = 0.011 at 1200∘C
umka2103 [35]

Answer:

The concentration of I at equilibrium = 3.3166×10⁻² M

Explanation:

For the equilibrium reaction,

I₂ (g) ⇄ 2I (g)

The expression for Kc for the reaction is:

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Given:

\left[I_2_{Equilibrium} \right] = 0.10 M

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Applying in the above formula to find the equilibrium concentration of I as:

0.011=\frac {\left[I_{Equilibrium} \right]^2}{0.10}

So,

\left[I_{Equilibrium} \right]^2=0.011\times 0.10

\left[I_{Equilibrium} \right]^2=0.0011

\left[I_{Equilibrium} \right]=3.3166\times 10^{-2}\ M

<u>Thus, The concentration of I at equilibrium = 3.3166×10⁻² M</u>

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3 years ago
The metal tantalum becomes superconducting at temperatures below 4.483 K. Calculate the temperature at which tantalum becomes su
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Answer:

The correct answer is "-268.667°C".

Explanation:

Given:

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= 4.483 K (below)

Now,

The formula of temperature conversion will be:

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By putting the values, we get

⇒            =4.483-273.15

⇒            =-268.667^{\circ} C

Thus the above is the correct answer.

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2 years ago
How many moles of Cu(OH)2 will be produced if given 1 mole<br> KOH.
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0.032 mole

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Please mark me as brainliest

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