Answer: The Porsche Wins. Arrives 19secs earlier before the Honda.
Explanation: The head start of 1secs corresponded with the difference in acceleration {3.5m/s² - 3m/s²}=0.5m/s²
Using the first equation of motion we obtain the velocity which correspond to this acceleration (0.5m/s²) and time of 1secs where initial velocity u = 0
V = u + at
V= 0 + at
V = 0.5 * 1 = 0.5m/s
Now let find the velocity of each of the car.
If V. a
0.5m/s 0.5m/s²
........m/s. 3.5m/s²
Velocity of porche Vp
= (3.5/0.5) * 0.5 = 3.5 m/s
Also if. V. a
0.5m/s. 0.5m/s²
.....m/s. 3 m/s²
Velocity of Honda Vh
= {3/0.5} * 0.5 = 3m/s
So let's find the time t taken by both cars to cover the distance of 400m
Recall,
Velocity = distance/time
Time t = distance/velocity
For Porche, t = 400/3.5 =114.29secs
For Honda, t = 400/3 = 133.33secs
Looking critically, we noticed that Porche car took shorter time.
The difference In time is
= (133.33 - 114.29)secs = 19.04secs
