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3 years ago

What type of resource can be regenerated or replenished by biochemicl cycles

1 answer:

5 0

A: A resource that will always be there, can be replenished by the biogeochemical cycles. B: Can regenerate if they are alive or can be replenished by biochemical cycles if they are non living.

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Who was the scientist who gave us the laws of motion?.

timurjin [86]

Answer:

Isaac Newton

Explanation:

Newton's laws of motion, three statements describing the relations between the forces acting on a body and the motion of the body.

3 0

2 years ago

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A block rests on a ?at plate that executes vertical simple harmonic motion with a period of 0.58s.

SVETLANKA909090 [29]

Answer:

maximum amplitude = 0.08 m

Explanation:

Given that

Time period T= 0.58 s

acceleration of gravity g= 9.8 m/s²

We know that time period of simple harmonic motion given as

T = 2π/ω

0.58 = 2π/ω

ω = 10.83rad/s

ω=angular frequency

Lets take amplitude = A

The maximum acceleration given as

a= ω² A

The maximum acceleration should be equal to g ,then block does not separate

a= ω² A

9.8 = 10.83² A

A = 0.08m

maximum amplitude = 0.08 m

8 0

3 years ago

Read 2 more answers

If Judy walks 2 blocks north, 5 blocks west, and then 2 blocks south, what is her final

VladimirAG [237]

Answer: 2 blocks east if i'm not mistaken.

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3 years ago

a large parallel plate capacitor has plate seperation of 1.00 cm and plate area of 314 cm^2. The capacitor is connected across a

Whitepunk [10]

Answer:

$W = -2.76\times 10^{-9}~J$

Explanation:

The work done on the capacitor is equal to the difference in potential energy stored in the capacitor in two different cases.

The potential energy is given by the following formula:

$U = \frac{1}{2}CV^2$

where C can be calculated using the plate separation and area.

$C = \epsilon\frac{A}{d} = \epsilon\frac{0.0314}{0.01} = 3.14\epsilon$

Therefore, the potential energy in the first case is

$U = \frac{1}{2}3.14\epsilon (20)^2 = 628\epsilon$

In the second case:

$C_2 = \epsilon\frac{A}{d} = \epsilon\frac{0.0314}{0.02} = 1.57\epsilon\\U = \frac{1}{2}C_2 V^2 = \frac{1}{2}1.57\epsilon (20)^2 = 314\epsilon$

The permittivity of the air is very close to that of vacuum, which is 8.8 x 10^-12.

So, the difference in the potential energy is

$W = U_2 - U_1 = \epsilon(314 - 628) = -314 \times 8.8 \times 10^{-12} = -2.76\times 10^{-9}~J$

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3 years ago

A body of mass 120 g is taken vertically upwards to reach the height of 5m,claculate work done

Anuta_ua [19.1K]

FOLLOW ME FOR CLEARING YOUR NEXT DOUBT

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3 years ago