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2 years ago

What will happen to the brightness of a string of bulbs hooked up in series when you increase the number of bulbs in the string?

1 answer:

3 0

<span>Each light in the string will get dimmer. Let us look at what is causing this. The scenario provided is that of a Series circuit. In the case of a series circuit, the current flowing through each of the load (String of bulbs in our example) is same, while the voltage drops equally across all the bulbs (provided all the bulbs are of the same rating) For example if we have a 230 V AC supply, and we have connected 10 bulbs in series, the voltage across each of the bulbs is (230/10=23 V). As you can see, if you add more bulbs, the voltage at each bulb drops further, causing them to dim. Hence, each light in the string will get dimmer as you add more lights. Option (B) is the answer.</span>

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You drive a car for 2.0 h at 60 km/h, then for another 3.0 h at 85 km/h. What is your average velocity

Anon25 [30]

Answer:

Explanation:

Average velocity is found in the total displacement experienced in the trip divided by the total time it took to make this trip. If, for the first 2.0 hours, the car travels at 60 km/hr, then in 2.0 hours the car can travel 120 km; if it then travels for 3.0 at 85 km/hr, it can travel 255 km in the same direction. The total time this took was 5.0 hours. So doing the math and rounding correctly by following the rules for the adding and subtracting of sig fig's:

$v=\frac{120+255}{5.0}=\frac{380}{5.0}=76\frac{km}{hr}$

If you do not round when you add, the average velocity is 75 km/hr

8 0

2 years ago

what is the orbital speed for a satellite 3.5 x 10^8m from the center of mars? Mars mass is 6.4 x 10^23 kg

adell [148]

Answer:

v = 349.23 m/s

Explanation:

It is required to find the orbital speed for a satellite $3.5\times 10^8\ m$ from the center of mass.

Mass of Mars, $M=6.4\times 10^{23}\ kg$

The orbital speed for a satellite is given by the formula as follows :

$v=\sqrt{\dfrac{GM}{r}} \\\\v=\sqrt{\dfrac{6.67\times 10^{-11}\times 6.4\times 10^{23}}{3.5\times 10^8}} \\\\v=349.23\ m/s$

So, the orbital speed for a satellite is 349.23 m/s.

6 0

2 years ago

It takes 120 minutes for a man to ride his bicycle up the road to Alpe d'Huez in France. The vertical height of the climb is 1,1

Greeley [361]

First solve the potential energy of the biker. using the fomula:
PE = mgh
where m is the mass of the object
g is the acceleration due to gravity ( 9.81 m/s2)
h is the height

PE = 96 kg ( 1120 m ) ( 9.81 m/s2)
PE = 1054771.2 J
then power = Work / time
P = 1054771.2 J / ( 120 min ) ( 60 s / 1 min)
P = 146.5 W

8 0

3 years ago

A huge (essentially infinite) horizontal nonconducting sheet 10.0 cm thick has charge uniformly spread over both faces. The uppe

Nonamiya [84]

Answer:

6.78 X 10³ N/C

Explanation:

Electric field near a charged infinite plate

= surface charge density / 2ε₀

Field will be perpendicular to the surface of the plate for both the charge density and direction of field will be same so they will add up.

Field due to charge density of +95.0 nC/m2

E₁ = 95 x 10⁻⁹ / 2 ε₀

Field due to charge density of -25.0 nC/m2

E₂ = 25 x 10⁻⁹ / 2ε₀

Total field

E = E₁ + E₂

= 95 x 10⁻⁹ / 2 ε₀ + 25 x 10⁻⁹ / 2ε₀

= 6.78 X 10³ N/C

4 0

2 years ago

An object is shot upwards, from the ground, with an initial velocity of 120

Alex777 [14]

Answer: 30 metres

Explanation:

Initial velocity of object = 120m/s

Time taken = 4.0s

Distance covered by object = ?

Recall that distance = (Change in velocity / Time taken)

Distance = (120m/s)/4.0s

= (120m/s) / 4.0s

= 30m

Thus, the object will be 30 metres high

6 0

2 years ago