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never [62]
3 years ago
7

What will happen to the brightness of a string of bulbs hooked up in series when you increase the number of bulbs in the string?

Physics
1 answer:
gtnhenbr [62]3 years ago
3 0
<span>Each light in the string will get dimmer. Let us look at what is causing this. The scenario provided is that of a Series circuit. In the case of a series circuit, the current flowing through each of the load (String of bulbs in our example) is same, while the voltage drops equally across all the bulbs (provided all the bulbs are of the same rating) For example if we have a 230 V AC supply, and we have connected 10 bulbs in series, the voltage across each of the bulbs is (230/10=23 V). As you can see, if you add more bulbs, the voltage at each bulb drops further, causing them to dim. Hence, each light in the string will get dimmer as you add more lights. Option (B) is the answer.</span>
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Electrically inert metal ball A is connected to the ground by a wire. What happens to the charge of this ball if you bring a neg
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) A steel guitar string with a diameter of 1.00 mm is stretched between supports 80.0 cm apart. The temperature is 0.0°C. (a) Fi
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Two blocks of masses M 1 and M 2 are connected by a massless string that passes over a massless pulley as shown in the figure. M
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The mass M1 is 7.8 kg

Explanation:

Block M1 is hanging on the string while block M2 is on the frictionless ramp.

We have to write the equations of motion for the two blocks.

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M_1 g - T = M_1 a

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M_1 is the mass of the block

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a is the acceleration of the system

- For M2, the only two forces acting on it are the tension in the string T (acting up along the ramp) and the component of the gravity acting down along the ramp, M_2 g sin \theta. So the equation of motion is

T-M_2 g sin \theta = M_2 a

where

M_2 = 13.5 kg is the mass of the 2nd block

\theta=35.5^{\circ} is the angle of the ramp

In order for the two blocks to be in equilibrium, the acceleration must be zero:

a=0

So the two equations become:

M_1 g - T=0\\T-M_2 g sin \theta = 0

Isolating T from the 1st equation,

T=M_1 g

And substituting into the 2nd equation, we can find the value of the mass M_1:

M_1 g - M_2 g sin \theta = 0\\M_1 = M_2 sin \theta = (13.5)(sin 35.5^{\circ})=7.8 kg

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