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Karolina [17]
3 years ago
14

The mountains on the Moon were formed by what process?

Physics
1 answer:
elena-14-01-66 [18.8K]3 years ago
4 0

Answer: The mountains that we observe on the moon, from earth are those rims forming the lunar mountains and mountain ranges. It has formed due to the asteroidal impact on the surface of the moon, billions of years back, resulting in the depressions and the highland areas. Due to this impact, a huge amount of heat energy generated that eroded and melted much of the materials from the moon's surface.

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Why a car making a turn does not have constant velocity
BabaBlast [244]
A car making a turn is accelerating. Acceleration is defined as a change in speed or direction.
8 0
2 years ago
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In a hydraulic lift, the radius of the small and large pistons are
Gennadij [26K]

Answer:

the answer is 52.15cm×35.5

8 0
2 years ago
What is the mass defect of lithium? Assume the following: Atomic number of lithium = 3 Atomic mass of lithium = 7.0144 atomic ma
Mice21 [21]

<span>3 protons x 1.0073amu = 3.022 </span>
<span>4 neutrons x 1.0087amu = 4.035 </span>

<span>mass = 7.0567amu </span>
<span>mass defect = 7.0567 - 7.0144 = 0.0423amu.....B with your mass of Li</span>
6 0
3 years ago
A 1,250 W electric motor is connected to a 220 Vrms, 60 Hz source. The power factor is lagging by 0.65. To correct the pf to 0.9
Black_prince [1.1K]

Answer:

C = 46.891 \mu F

Explanation:

Given data:

v = 220 rms

power factor = 0.65

P = 1250 W

New power factor is 0.9 lag

we knwo that

s = \frac{P}{P.F} < COS^{-1} 0.65

S = \frac{1250}{0.65} < 49.45

s = 1923.09 < 49.65^o

s = [1250 + 1461 j] vA

P.F new = cos [tan^{-1} \frac{Q_{new}}{P}]

solving for Q_{new}

Q_{new} = P tan [cos^{-1} P.F new]

Q_{new} = 1250 [tan[cos^{-1}0.9]]

Q_{new} = 605.40 VARS

Q_C = Q - Q_{new}

Q_C = 1461 - 605.4 = 855.6 vars

Q_C = \frac[v_{rms}^2}{xc} =v_{rms}^2 \omega C

C = \frac{Q_C}{ v_{rms}^2 \omega}

C = \frac{855.6}{220^2 \times 2\pi \times 60}

C = 4..689 \times 10^{-5} Faraday

C = 46.891 \mu F

6 0
3 years ago
A woman on a bridge 95.6 m high sees a raft floating at a constant speed on the river below. She drops a stone from rest in an a
NARA [144]

Answer:

The speed of the raft is 1.05 m/s

Explanation:

The equation for the position of the stone is as follows:

y = y0 + v0 · t + 1/2 · g · t²

Where:

y = height of the stone at time t

y0 = initial height

v0 = initial speed

t = time

g = acceleration due to gravity

The equation for the position of the raft is as follows:

x = x0 + v · t

Where:

x = position of the raft at time t

x0 = initial position

v = velocity

t = time

To find the speed of the raft, we have to know how much time the raft traveled until the stone reached the river. For that, we can calculate the time of free fall of the stone:

y = y0 + v0 · t + 1/2 · g · t²      (v0=0 because the stone is dropped from rest)

If we place the origin of the frame of reference at the river below the bridge:

0 m = 95.6 m - 9.8 m/s² · t²

-95.6 m / -9,8 m/s² = t²

t = 3.12 s

We know that the raft traveled (4.84 m - 1.56 m) 3.28 m in that time, then the velocity of the raft will be:

x/t = v

3.28 m / 3.12 s = v

v = 1.05 m/s

5 0
2 years ago
Read 2 more answers
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