What happens to us is when we come into contact with water<span> in such a way that it impinges on our state of being. We, or our possessions, 'get </span>wet<span>'.
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Answer:
2 m/s
Explanation:
Applying,
The law of conservation of momentum
Total momentum before collision = Total momentum after collision
mu+m'u' = V(m+m')............... Equation 1
Where m = mass of the first freight car, m' = mass of the second freight car, u = initial velocity of the first freight car, u' = initial velocity of the second freight car, V = final combined velocity/ speed.
make V the subject of the equation
V = (mu+m'u')/(m+m')........... Equation 2
From the question,
Given: m = 1234 kg, m' = 2468 kg, u = 6 m/s, u' = 0 m/s (at rest)
Substitute these values into equation 2
V = [(1234×6)+(2468×0)]/(1234+2468)
V = 7404/3702
V = 2 m/s
Answer:
The force is 
The time is 
Explanation:
From the question we are told that
The mass of the car is 
The initial velocity of the car is 
The final velocity of the car is 
The acceleration is 
Generally the acceleration is mathematically represented as
=> 
=> 
converting to seconds
=>
Generally the force is mathematically represented as
=> 
=> 
Now converting to foot-pound-second we have
=>
Answer:
Explanation:
Given that,
Number of turns of coil
N = 50 turns
Initial area of plane
A1 = 0.18 m²
The coil it stretch to a no area in time t = 0.1s
No area implies that the final area is 0, A2 = 0 m²
Constant magnetic field strength
B = 1.51 T
EMF?
EMF is given as
Using far away Lenz law
ε = —N• dΦ/dt
Where Φ = BA
Then,
ε = —N• d(BA)/dt
Since B is constant,
ε = —N•B dA/dt
ε = —N•B (∆A/∆t)
ε = —N•B(A2—A1)/(t2-t1)
ε = —50 × 1.51 (0—0.18)/(0.1—0)
ε =—75.5 × —0.18 / 0.1
ε = 135.9 V
The induced EMF is 135.9V
Fleming’s left hand rule stated that if the index finger points toward magnetic flux, the thumb towards the motion of the conductor, then the middle finger points towards the induced emf.
Since the area lines in the plane, then the induced emf will be out of the page
The force between the two point charge when they are separated by 18 cm is 3 N
<h3>How do I determine the force when they are 18 cm apart?</h3>
Coulomb's law states as follow:
F = Kq₁q₂ / r²
Cross multiply
Fr² = Kq₁q₂
Kq₁q₂ => constant
F₁r₁² = F₂r₂²
Where
- F₁ and F₂ are the initial and new force
- r₁ and r₂ are the initial and new distance apart
With the above formula, we can obtain the force between the two point charge when they are 18 cm apart. Details below:
- Initial distance apart (r₁) = 6 cm
- Initial force of attraction (F₁) = 27 N
- New distance apart (r₂) = 18 cm
- New force of attraction (F₂) =?
F₁r₁² = F₂r₂²
27 × 6² = F₂ × 18²
972 = F₂ × 324
Divide both side by 324
F₂ = 927 / 324
F₂ = 3 N
Thus, the force when they are 18 cm apart is 3 N
Learn more about force:
brainly.com/question/28569085
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