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KATRIN_1 [288]
3 years ago
12

A gas with constant temperature has a pressure of 4 atm this pressure changes to 0.2 atm causing the volume to increase to 500L

what was the initial volume of the gas
Physics
2 answers:
schepotkina [342]3 years ago
8 0

Answer:

25L

Explanation:

The problem can be solved using Boyle's law for the volume and pressure of a gas at constant temperature:

P_{1}V_{1}=P_{2}V_{2}

Where the quantities with sub-index 1 are the initial conditions for the gas and the quantities with sub-index 2 are for the final conditions of the gas.

We want to know the initial volume, this is:

V_{1}=\frac{P_{2}V_{2}}{P_{1}}

we also know from the problem that

P_{1}=4atm\\P_{2}=0.2atm\\V_{2}=500L

Thus, the initial volume V1 is:

V_{1}=\frac{0.2atm*500L}{4atm}

V_{1}=25L

Alexxx [7]3 years ago
4 0
Using the combined gas law of P1V1=P2V2 and plug it in you get (4)V1 for you don't have initial volume = (0.2)(500) --> 4V1=100, divide by the coefficient on both sides and you get V1=25
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