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Svetllana [295]
3 years ago
11

A rock is dropped from a distance RE above the surface of the earth, and is observed to have kinetic energy K1 when it hits the

ground. An identical rock is dropped from twice the height (2RE) above the earth’s surface and has kinetic energy K2 when it hits. RE is the radius of the earth. what is k2/k1?
Physics
1 answer:
goblinko [34]3 years ago
8 0

Answer:

\dfrac{K_2}{K_1}=\dfrac{4}{3}

Explanation:

When an object strikes the ground, the potential energy of the rock gets converted to the kinetic energy.

A rock is dropped from a distance R_e above the surface of the earth and is observed to have kinetic energy K_1 when it hits the ground.

For another rock, It is dropped from twice the height 2R_e above the earth’s surface and has kinetic energy K_2 when it hits.              

For the first rock, K_1=GMm(\dfrac{1}{R_e}-\dfrac{1}{2R_e})=\dfrac{GMm}{2R_e}..............(1)

For the second rock, K_2=GMm(\dfrac{1}{R_e}-\dfrac{1}{3R_e})=\dfrac{2GMm}{3R_e}..............(2)

Dividing equation (2) by (1) we get :

\dfrac{K_2}{K_1}=\dfrac{4}{3}

Hence, this is the required solution.                                            

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Vinil7 [7]

Answer:

Net force

Explanation:

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3 0
3 years ago
This is a problem about a child pushing a stack of two blocks along a horizontal floor. The masses of the blocks, and the coeffi
Rufina [12.5K]

Answer:

 N = 23.4 N

Explanation:

After reading that long sentence, let's solve the question

The contact force is the so-called normal in this case we can find it by writing the translational equilibrium equation for the y axis

            N - w₁ -w₂ =

            N = m₁ g + m₂ g

            N = g (m₁ + m₂)

let's calculate

            N = 9.8 (0.760 + 1.630)

            N = 23.4 N

This is the force of the support of the two blocks on the surface.

7 0
3 years ago
What do we mean by the event horizon of a black hole?
TEA [102]
<h2>Answer:</h2>

The event horizon is the surface of a black hole, it is the border of space-time in which the events on one side of it can not affect an observer on the other side.  

That is, at this border also called "point of no return", nothing can escape (not even light) and no event that occurs within it can be seen from outside.

 

5 0
4 years ago
Read 2 more answers
When 597 J of heat are added to a gas, it expands. Its internal energy increases by 318 J. How much work does the gas do? (Unit=
damaskus [11]

The magnitude of work done by the gas is 279 J and the sign is negative so W = -279 J as work is done by the system.

<u>Explanation:</u>

According to first law of thermodynamics, the change in internal energy of the system is equal to the sum of the heat energy added or released from the system with the work done on or by the system. If the heat energy is added to the system to perform a certain work, then the heat energy is taken as positive, while it will be negative when the heat energy is released from the system.

Similarly, in this case, the heat energy of 597 J is added to the system. So the heat energy will be positive, while the gas expansion occurs means work is done by the system.

          ΔU = Q+W

Since ΔU is the change in internal energy which is given as 318 J and the heat energy added to the system is Q = 597 J.

Then the work done by the gas = ΔU - Q = 318 J - 597 J = - 279 J.

As the work is done by the system, so it will be denoted in negative sign and the magnitude of work done by the gas is 279 J.

7 0
3 years ago
Elaborate on the reason why heating water up will increase the rate of dissolving for a solute.
Harrizon [31]
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5 0
3 years ago
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