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3 years ago

Could anyone help with this question I do

Physics

2 answers:

ra1l [238]3 years ago

8 0

which of those can we not get back once it has been used, the answer is oil or petroleum

dedylja [7]3 years ago

7 0

That is a very good question and i think i know the answer but am not sure. C sunlight because once you use sunlight you cant use it again and again

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"The greater the height of an object, the *BLANK* its gravitational potential energy."

-Dominant- [34]

Answer:

the greater the height of an object the *greater* its gravitational potential energy

greater

3 0

2 years ago

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Dx= 7.14m and Dy = -7.55m What is the direction and magnitude of the vector

KengaRu [80]

The Magnitude of the Vector is 10.39m and the direction of the vector is - 46.7°.

Explanation:

GIven dx=7.14m and dy= -7.55m,

The Magnitude of the Vector= $\sqrt{dy^{2} +dx^{2} }$

Magnitude d= $\sqrt{(7.14)^{2} +(-7.55)^{2} }$ .

d= $\sqrt{50.97+57}$

d= $\sqrt{107.98}$

d= 10.39m.

Direction Ф = $tan^{-1}$ $\frac{dy}{dx}$

= $tan^{-1}$ $\frac{-7.55}{7.14}$

= $tan^{-1}$ (-1.06)

Ф = - 46.7°.

5 0

3 years ago

A very long, straight solenoid with a cross-sectional area of 2.00 cm2 is wound with 94.1 turns of wire per centimeter. Starting

julia-pushkina [17]

Yeah I have no clue what you saw me on lol yeah I

5 0

3 years ago

Estimate the average force that a baseball pitcher's hand exerts on a 0.145-kg baseball as he throws a 40-m/s pitch. Assume the

Kitty [74]

Answer:

38.67 N

Explanation:

v = Final velocity = 40 m/s

u = Initial velocity

m = Mass of ball = 0.145kg

s = Displacement of ball = 3 m

Equation of motion

$v^2-u^2=2as\\\Rightarrow a=\frac{v^2-u^2}{2s}\\\Rightarrow a=\frac{40^2-0^2}{2\times 3}=\frac{800}{3}\ m/s^2$

F=ma

$\\\Rightarrow F=0.145\times \frac{800}{3}\\\Rightarrow F=38.67\ N$

∴ Average force that a baseball pitcher's hand exerts on the ball is 38.67 N

6 0

3 years ago

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Assume it takes 8.00 min to fill a 50.0-gal gasoline tank. (1 U.S. gal = 231 in.3) (a) Calculate the rate at which the tank is f

vagabundo [1.1K]

The volumetric rate or flow rate of a fluid is defined as the amount of the volume of a fluid circulating on a surface per unit of time. In this case we have units given initially: Gallons and minutes. For the first part we will convert the minutes to seconds, and we will obtain the flow rate under that measure. For the second case we will convert the gallons to cubic meters and obtain the desired value. Recall the following conversion rates,

$1 min = 60s$