Answer:
I think frequency not sure though
How frequently a wave or vibration occurs during a span of time, determines the waves frequency. Frequency is the number of waves per unit time. The unit for frequency if a Hertz ( 1/second). The speed a wave travels is the wavelength multiplied by this frequency. The amplitude of a wave is the maximum distance the wave is displaced.
Answer:
3.85*10^8m
Explanation:
We know that
Speed v = distance/time t
So distance = v x t
So = 3*10^8 x 2.56s
= distatance = 7.7*10^8m
However this is double the distance from the earth to the moon, so to get distance from earth to the moon we divide by 2
7.7*10^8/2= 3.85*10^8m
Answer:
1. 8437500 N
2. The force between the two charges is attractive.
Explanation:
1. Determination of the force between the two charges.
Charge 1 (q₁) = –2.0 C
Charge 2 (q₂) = 3.0 C
Distance apart (r) = 80 m
Electrical constant (K) = 9×10⁹ Nm²/C²
Force (F) =?
F = Kq₁q₂ / r²
F = 9×10⁹ × 2 × 3 / 80²
F = 5.4×10¹⁰ / 6400
F = 8437500 N
Thus, the force of attraction between the two charges is 8437500 N
2. From the question given, the charges are:
Charge 1 (q₁) = –2.0 C
Charge 2 (q₂) = 3.0 C
We understood that like charges repels while unlike charges attract. Since the two charges (i.e –2 C and 3 C) has opposite signs, it means they will attract each other.
Thus the force between them is attractive.
The particle motion increases, and temperature increases. Hope this helps GIVE ME BRANLIST
Answer:
- The distance between the charges is 5,335.026 m
Explanation:
To obtain the forces between the particles, we can use Coulomb's Law in scalar form, this is, the force between the particles will be:
where k is Coulomb's constant, 
and 
are the charges and d is the distance between the charges.
Working a little the equation, we can take:
And this equation will give us the distance between the charges. Taking the values of the problem
(the force has a minus sign, as its attractive)
And this is the distance between the charges.
