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tatyana61 [14]
3 years ago
12

What type of molecule is shown below

Chemistry
1 answer:
Kobotan [32]3 years ago
4 0

Answer is: C alkane.

Name of this molecule is n-hexane.

Hexane is alkane (acyclic saturated hydrocarbon, carbon-carbon bonds are single) of six carbon atoms.

Carbon atoms in hexane have sp3 hybridization.

In sp3 hybridization hybridize one s-orbital and three p-orbitals of carbon atom.

Alkene has one double bond and alkyne has one triple bond.

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Describes two uses of surfactants at least one must be something that was not described in the passage
Morgarella [4.7K]

Answer:

We don't have the passage.  A random sampling of surfactant uses includes:

  • removal of oily materials from objects (clothes and dishes)
  • forms remarkable structures called bubbles
  • Assists in forming emulsions (e.g., mayonaise and paints)

Explanation:

The structure of a surfactant makes one end of a molecule hydrophilic and the other end hydrophobic.  In water, they self-assemble into micelles, an arrangement in which the hydrophobic ends align towards the center, and the hydrophilic ends are pointed outwards to the water.  This self-assembly is apparant when bubbles are made.  The  molecules quickly align themselves such that the hyrophilic ends are oriented inwards towards a thin layer of water and the hydrophobic ends are pointed outward to the air.  This arrangement allows a mono-molecular sphere of water molecules to remain stable enough to float, reflect light, and please.  These same properties allow the inverse to occur.  Soap molecules surround a hydrophobic mass (e.g., the hamburger grease on your shirt) and solubilize it into small micelles which are then carried away in the surrounding water.

4 0
2 years ago
Which statement identifies the element arsenic?
insens350 [35]

Answer : Option A) Atomic number of Arsenic is 33.


Explanation : Arsenic contains same number of protons in its atomic nucleus. In arsenic there are 33 protons found in the atomic nucleus. Hence, the atomic number will be 33. It has 5 valence electrons in its outermost shell, which is also called as valence shell. So, its valency becomes 5.

8 0
3 years ago
Read 2 more answers
In these chemical compounds, c is for carbon, o is for oxygen, n is for nitrogen, and k is for potassium. Which chemical compoun
Jet001 [13]

Answer:

carbon because organic compounds are made up of hydrogen and carbon

8 0
2 years ago
How many electrons are in the outermost principal energy level of an atom of carbon in the ground state
Agata [3.3K]

Answer:

four electrons

Explanation:

Let us attempt to write the electronic configuration of carbon in the ground state. This electronic configuration will now be;

C- 1s2 2s2 2p2

The outermost principal energy level of carbon is the n=2 level which houses the 2s2 and 2p2, making a total of four electrons in the outermost principal energy level of an atom of carbon in the ground state.

5 0
2 years ago
A. Which reactant is the limiting reagent?
Tasya [4]

Answer:

a. Zinc is the limiting reactant.

b. m_{ZnBr_2}^{by\ Zn}=162.61gZnBr_2

c. m_{Br_2}^{leftover}=6.6g

Explanation:

Hello there!

a. In this case, when zinc metal reacts with bromine, the following chemical reaction takes place:

Zn+Br_2\rightarrow ZnBr_2

Thus, since zinc and bromine react in a 1:1 mole ratio, we can compute their reacting moles to identify the limiting reactant:

n_{Zn}=47.2g*\frac{1mol}{65.38g} =0.722molZn\\\\n_{Br_2}=122g*\frac{1mol}{159.8g} =0.763molBr_2

Thus, since zinc has the fewest moles we infer it is the limiting reactant.

b. Here, we compute the grams of zinc bromide via both reactants:

m_{ZnBr_2}^{by\ Zn}=0.722molZn*\frac{1molZnBr_3}{1molZn} *\frac{225.22gZnBr_2}{1molZnBr_2} =162.61gZnBr_2\\\\m_{ZnBr_2}^{by\ Br_2}=0.763molBr_2*\frac{1molZnBr_3}{1molBr_2} *\frac{225.22gZnBr_2}{1molZnBr_2} =171.95gZnBr_2

That is why zinc is the limiting reactant, as it yields the fewest moles of zinc bromide product.

c. Here, since just 0.722 mol of bromine would react, we compute the corresponding mass:

m_{Br_2}^{reacted}=0.722molBr_2*\frac{159.8gBr_2}{1molBr_2} =115.4gBr_2

Thus, the leftover of bromine is:

m_{Br_2}^{leftover}=122g-115.4g\\\\m_{Br_2}^{leftover}=6.6g

Best regards!

8 0
3 years ago
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