A large tuning fork has a lower or higher frequency than a small tuning fork?

Physics

1 answer:

netineya [11]3 years ago

5 0

A large tuning fork makes a lower frequency than a small one

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Answer:

a) $v = 34.607\,\frac{m}{s}$ (Positive), b) $e = 0.803$ . The collision is not perfectly elastic.

Explanation:

a) The collision can be described by the Principle of Momentum Conservation and Principle of Energy Conservation:

$(0.140\,kg)\cdot (0\,\frac{m}{s} ) + (0.0085\,kg)\cdot (320\,\frac{m}{s} ) = (0.0085\,kg)\cdot (-250\,\frac{m}{s} ) + (0.140\,kg)\cdot v$

The final velocity of the rock is:

$v = 34.607\,\frac{m}{s}$

b) The coefficient of restitution is the best criterion to distinguish elastic collsions from inelastic collisions, such criterion is the ratio of final energy of the system to initial energy of the system:

$e = \frac{\frac{1}{2}\cdot [(0.140\,kg)\cdot (34.607\,\frac{m}{s} )^{2}+(0.0085\,kg)\cdot (-250\,\frac{m}{s} )^{2}] }{\frac{1}{2}\cdot [(0.140\,kg)\cdot (0\,\frac{m}{s} )^{2}+(0.0085\,kg)\cdot (320\,\frac{m}{s} )^{2}] }$