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vladimir2022 [97]
3 years ago
15

A large tuning fork has a lower or higher frequency than a small tuning fork?

Physics
1 answer:
netineya [11]3 years ago
5 0
A large tuning fork makes a lower frequency than a small one
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what is the gravitational potential energy of a 150-kg object that is suspended 5-m above the earth's surface
77julia77 [94]
150x5x9.7(gravity on earth)=7275
7 0
3 years ago
Swings are usually made out of materials that do not conduct heat easily, so that children will not burn themselves as they play
Irina18 [472]

the correct answer is D: all of these

8 0
3 years ago
Two objects attract each other gravitationally. If the distance between their centers decreases by a factor of 2, how does the g
kramer

Answer:

The gravitational force between them increases by a factor of 4

Explanation:

Gravitational force is a force of attraction between two objects with masses M and m which are separated by a distance R. It is given mathematically as:

Fg = GMm/R²

Where G = Gravitational constant.

If the distance between their centers, R, decreases by a factor of 2, then it means the new distance between their centers is:

r = R/2

Hence,the gravitational force becomes:

Fg = GMm/r²

Fg = GMm/(R/2)²

Fg = GMm/(R²/4)

Fg = 4GMm/R²

Hence,the gravitational force increases by a factor of 4.

6 0
3 years ago
Using a 683 nm wavelength laser, you form the diffraction pattern of a 1.1 mm wide slit on a screen. You measure on the screen t
n200080 [17]

Answer:

10.2 m

Explanation:

The position of the dark fringes (destructive interference) formed on a distant screen in the interference pattern produced by diffraction from a single slit are given by the formula:

y=\frac{\lambda (m+\frac{1}{2})D}{d}

where

y is the position of the m-th minimum

m is the order of the minimum

D is the distance of the screen from the slit

d is the width of the slit

\lambda is the wavelength of the light used

In this problem we have:

\lambda=683 nm = 683\cdot 10^{-9} m is the wavelength of the light

d=1.1 mm = 0.0011 m is the width of the slit

m = 13 is the order of the minimum

y=8.57 cm = 0.0857 m is the distance of the 13th dark fringe from the central maximum

Solving for D, we find the distance of the screen from the slit:

D=\frac{yd}{\lambda(m+\frac{1}{2})}=\frac{(0.0857)(0.0011)}{(683\cdot 10^{-9})(13+\frac{1}{2})}=10.2 m

6 0
3 years ago
What is a suspension bridge- in your own words please and ty
PIT_PIT [208]
A bridge supported by vertical cables which then leads to more support from larger cables.
4 0
3 years ago
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