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Lapatulllka [165]
4 years ago
6

A basketball has a mass of 1 kg and is traveling 12 m/s. How fast would a 6 kg bowling ball have to travel to have the same mome

ntum?
1 m/s
2 m/s
3 m/s
4 m/s

Physics
1 answer:
Pavel [41]4 years ago
3 0
Plz feel free to adk more if u hv any confusion!!!

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geniusboy [140]

many increases and decreases but declined overall

6 0
3 years ago
Read 2 more answers
Suppose air resistance does not exist, roughly what would be the velocity of a 10 lb object 5-seconds into free fall off of a 50
ira [324]

Answer:

Correct answer :  v = 50 m/s

Explanation:

The movement described is a free fall with no initial velocity and we will use the following formula:

v = g · t   we take that g = 10 m/s²

v = 10 m/s²· 5 s = 50 m/s

v = 50 m/s

God is with you!!!

4 0
4 years ago
WhAt is this question??????????
valina [46]

Answer:

Period = 7

Group = Actinides group

Family = Actinides Family

Explanation:

uranium found in seventh row or seventh period of the periodic table.

uranium is the member of Actinoides group it is also called Actinide group, And it has element whose atomic is number is 89 to 103. The atomic number of the uranium is 92. So, the uranium element is belongs to Actinide group

Uranium found in actinide family of periodic table, and actinides family has element whose atomic number is greater than or equal to 89 and less than or equal to 103.

8 0
3 years ago
How much heat does it take to bring 0.12 kg of liquid water at 100c to steam at 140c
Vadim26 [7]

Answer:

162

Explanation:

4 0
3 years ago
The potential difference between two parallel conducting plates in vacuum is 165 V. An alpha particle with mass of 6.50×10-27 kg
shepuryov [24]

Answer:

kinetic energy (K.E) = 5.28 ×10⁻¹⁷            

Explanation:

Given:

Mass of  α particle (m) = 6.50 × 10⁻²⁷ kg

Charge of  α particle (q) = 3.20 × 10⁻¹⁹ C

Potential difference ΔV = 165 V

Find:

kinetic energy (K.E)

Computation:

kinetic energy (K.E) = (ΔV)(q)

kinetic energy (K.E) = (165)(3.20×10⁻¹⁹)

kinetic energy (K.E) = 528 (10⁻¹⁹)

kinetic energy (K.E) = 5.28 ×10⁻¹⁷              

4 0
3 years ago
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