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Lapatulllka [165]

3 years ago

6

A basketball has a mass of 1 kg and is traveling 12 m/s. How fast would a 6 kg bowling ball have to travel to have the same mome

ntum?
1 m/s
2 m/s
3 m/s
4 m/s

1 answer:

Pavel [41]3 years ago

3 0

Plz feel free to adk more if u hv any confusion!!!

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If you were to drop a rock from a tall building, assuming that it had not yet hit the ground, and neglecting air resistance, how

taurus [48]

T=2s
g=10m/s2
h=?
free fall: h=gt2/2
              h= 10*4/2
               h=40/2
              h=20m

3 0

3 years ago

An electron with speed 2.45 x 10^7 m/s is traveling parallel to a uniform electric field of magnitude 1.18 x 10^4N/C . How much

cupoosta [38]

Answer:

time will elapse before it return to its staring point is 23.6 ns

Explanation:

given data

speed u = 2.45 × $10^{7}$ m/s

uniform electric field E = 1.18 × $10^{4}$ N/C

to find out

How much time will elapse before it returns to its starting point

solution

we find acceleration first by electrostatic force that is

F = Eq

here

F = ma by newton law

so

ma = Eq

here m is mass , a is acceleration and E is uniform electric field and q is charge of electron

so

put here all value

9.11 × $10^{-31}$ kg ×a = 1.18 × $10^{4}$ × 1.602 × $10^{-19}$

a = 20.75 × $10^{14}$ m/s²

so acceleration is 20.75 × $10^{14}$ m/s²

and

time required by electron before come rest is

use equation of motion

v = u + at

here v is zero and u is speed given and t is time so put all value

2.45 × $10^{7}$ = 0 + 20.75 × $10^{14}$ (t)

t = 11.80 × $10^{-9}$ s

so time will elapse before it return to its staring point is

time = 2t

time = 2 ×11.80 × $10^{-9}$

time is 23.6 × $10^{-9}$ s

time will elapse before it return to its staring point is 23.6 ns

7 0

3 years ago

How does the mass affect the speed as it rolls down a slope?

VikaD [51]

As we use the Kinetic energy and the equation is 1/2mv^2, changing its mass will change its speed and its energy. So more mass, more speed more energy. also the gravitational potential energy; mass x gravity x height; more mass and more height more speed as it go down to the slope! Hope it helps!

6 0

3 years ago

What’s being done to the brake fluid in the above photo?

ch4aika [34]

Answer:

D. Checking to see if the brake fluid is contaminated

Explanation:

5 0

3 years ago

a car headed north at 15 m/s accelerates for 4.25 s to reach a velocity of 28.3 m/s. What is the acceleration of the car?

Liono4ka [1.6K]

<u>Answer:</u>

The acceleration of the car is $3.13 m/s^2$

<u>Explanation:</u>

In the question it is given that car initially heads north with a velocity $15 m/s$ . It then accelerates for $4.25 s$ and in the end its velocity is $28.3 m/s$ .

initial velocity $u = 15 m/s$

time $t=4.25 s$

final velocity $v=28.3 m/s$

The equation of acceleration is

$a= \frac{(v-u)}{t}$

$= \frac{(28.3-15)}{4.25} = \frac {13.3}{4.25} =3.13m/s^2$

The value of acceleration is positive, here since the car is speeding up. If it was slowing down the value of acceleration would be negative.

7 0

3 years ago