Characteristics of transition metals
1 answer:
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The given concentration of boric acid = 0.0500 M
Required volume of the solution = 2 L
Molarity is the moles of solute present per liter solution. So 0.0500 M boric acid has 0.0500 mol boric acid present in 1 L solution.
Calculating the moles of 0.0500 M boric acid present in 2 L solution:
Converting moles of boric acid to mass:
Therefore, 6.183 g boric acid when dissolved and made up to 2 L with distilled water gives 0.0500 M solution.
Answer:
ratio=0.996m/s
Explanation:
; M= molecular weight of compound;
RMS speed is inversly proportional to the molecular weight hence compound having less molecular weight will have more rms speed value.
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