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Igoryamba
3 years ago
5

Characteristics of transition metals

Chemistry
1 answer:
Tresset [83]3 years ago
6 0

Answer:  They are good conductors of heat and electricity.

they can be hammered or bent into shape easily.

they have high melting points (but mercury is a liquid at room temperature)

they are usually hard and tough.

they have high densities.

Explanation:

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Tony made 14L of lemonade for a party. His guests drank 9500mL of the lemonade. How many milliliters did Tony have left?
Anuta_ua [19.1K]
Since 9500 mL of lemonade equals 9.5 liters, that means that Tony has 4.5 liters left, because 9.5 + 4.5 = 14
7 0
3 years ago
Which of the following has the largest molecular weight? Question 2 options: NO2 N2O CO2 H2S
Marizza181 [45]

Answer:

NO2

I got it right

6 0
2 years ago
Which factors determine the length of a bond between two elements?
Tanya [424]

Answer:

The length of the bond is determined by the number of bonded electrons (the bond order). The higher the bond order, the stronger the pull between the two atoms and the shorter the bond length. Generally, the length of the bond between two atoms is approximately the sum of the covalent radii of the two atoms.

6 0
3 years ago
Describe how you would prepare approximately 2 l of 0.050 0 m boric acid, b(oh)3.
Elenna [48]

The given concentration of boric acid = 0.0500 M

Required volume of the solution = 2 L

Molarity is the moles of solute present per liter solution. So 0.0500 M boric acid has 0.0500 mol boric acid present in 1 L solution.

Calculating the moles of 0.0500 M boric acid present in 2 L solution:

2 L * \frac{0.0500 mol B(OH)_{3} }{1 L} = 0.100 mol B(OH)_{3}

Converting moles of boric acid to mass:

0.100 mol B(OH)_{3} * \frac{61.83 g}{mol B(OH)_{3}}   = 6.183 g

Therefore, 6.183 g boric acid when dissolved and made up to 2 L with distilled water gives 0.0500 M solution.


5 0
4 years ago
What is the ratio (in the form of a decimal) of the root-mean-square speed of 238UF6 to that of 235UF6 at constant temperature?
NNADVOKAT [17]

Answer:

ratio=0.996m/s

Explanation:

RMS=\sqrt{\frac{3RT}{M} }; M= molecular weight of compound;

RMS speed is inversly proportional to the molecular weight hence compound having less molecular weight will have more rms speed value.

V1 for 238 UF_{6}; M1=238+114=352g/mole

V1 for 235 UF_{6}; M1=238+114=352g/mole

V1=\sqrt{\frac{3RT}{352} };

V2=\sqrt{\frac{3RT}{349} };

\frac{V1}{V2}=ratio of 238UF_{6} F6 to 235UF_{6}=\sqrt{\frac{349}{352} };

\frac{V1}{V2} =0.9957m/s;

\frac{V1}{V2} =0.996m/s;

4 0
3 years ago
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