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Soloha48 [4]
4 years ago
11

How are volcanoes and wind similar? A. They both create igneous rock. B. They both can be constructive forces. C. They both form

deltas. D. They are both a form of physical weathering.
Physics
1 answer:
Gekata [30.6K]4 years ago
6 0

B. They both can be constructive forces.

Both volcanos and wind can shape the landscape... volcanos using eruptions and lava, wind using wind erosion when it gets "windy".

Hope this helps.

r3t40

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Give an example of a mixture that contains more than one state of matter
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GEL IT IS COMBINATION OF SOLID AND LIQUID
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Three rocks, each of varying mass and volume, are released from a window at the same time. The window is at height h above the g
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All three rocks will achieve the same speed
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An apple falls straight down from a tree and hits the ground in approximately 0.75 seconds. Based on this information, which is
Mnenie [13.5K]

Answer:

y = 2.76 [m]

Explanation:

We can find the distance of the fall of the apple using the following kinematic equation, we have to emphasize that this is a typical problem of free fall, so the initial speed is zero, then we give the initial data.

t = time = 0,75[s]

g = gravity = 9.81[m/s^2]

v0 = 0

y = v_{0}*t+0.5*g*t^{2}\\ y=0.5*(9.81)*(0.75)^{2}\\y= 2.76[m]

3 0
4 years ago
A student on a skateboard is moving at a speed of 1.40 m/s at the start of a 2.15 m high and 12.4 m long incline. The total mass
saw5 [17]

Answer:

W = 609.97J

Explanation:

In order to calculate the work done by the student, you take into account that the total work is equal to the change of the kinetic energy of the student, as follow:

W_T=\Delta K\\\\W+W_g-W_f=\frac{1}{2}m(v^2-v_o^2)\\\\W+Mgsin\alpha d-F_fd=\frac{1}{2}m(v^2-v_o^2)         (1)

The work done by the friction force is negative because it is against the motion of the student.

W: work done by the student = ?

Wf: work done by the friction force

Wg: work done by the gravitational force

Ff: total friction force = 41.0N

m: mass of the skateboard = 53.0kg

d: distance traveled by the student

v: final speed of the student = 6.90m/s

vo: initial speed of the student = 1.40m/s

α: angle of the incline

You first calculate the distance d, with the Pythagoras' theorem

d=\sqrt{(2.15m)^2+(12.4m)^2}=12.58m

Furthermore, the angle α is:

\alpha=tan^{-1}(\frac{2.15m}{12.4m})=9.83\°

Then, you solve the equation (1) for W and replace the values of all parameters:

W=\frac{1}{2}m(v^2-v_o^2)+F_fd-Mgsin\alpha d\\\\W=\frac{1}{2}(53.0kg)((6.90m/s)^2-(1.40m/s)^2)+(41.0N)(12.58m)\\-(53.0kg)(9.8m/s^2)sin(9.83\°)(12.58m)\\\\W=609.97J

The work done by the student is 609.97J

6 0
4 years ago
A 7.7cm length of straight wire run horizontally along a north south line . The wire carries a 3.45 current flowing northward th
Maurinko [17]

Answer:

F = 0.332 N in the east direction

Explanation:

Length, L = 7.7 cm = 7.7 * 0.01 = 0.077 m(along the north south)

Current, I = 3.45 A (northwards)

Magnetic field, B = 1.25 T (vertically upwards)

The magnitude of the force is given by, F = ILBsin90

F = 3.45 * 0.077 * 1.25 * 1

F = 0.332 N

The direction of the force is calculated using the Right Hand Thumb Rule:

It states that "Hold the wire carrying current in your right hand so that the thumb points along the wire in the direction of the current, then the fingers will encircle the wire in the direction of the lines of magnetic force."

Based on the Right Hand Thumb Rule, the magnetic force will act in the east direction

3 0
3 years ago
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