All categories

3 years ago

How many formula units make up 12.8 g of magnesium chloride ( MgCl2)? Express the number of formula units numerically.

Chemistry

1 answer:

Advocard [28]3 years ago

8 0

Answer:

For 12.8 g there 0.807 × 10³ formula units.

Explanation:

Given data:

Mass of MgCl₂ = 12.8 g

Formula units for given mass = ?

Solution:

First of all we will calculate the number of moles.

Number of moles = mass/molar masss

Number of moles = 12.8 g/ 95.211 g/mol

Number of moles = 0.134 mol

According to the Avogadro number,

one moles = 6.022 × 10³ formula units

For 0.134 mol,

0.134 × 6.022 × 10³ formula units

0.807 × 10³ formula units

For 12.8 g there 0.807 × 10³ formula units.

You might be interested in

What grade percentage is developing, proficient, exceeding, and emerging?

user100 [1]

Answer:

Grade A is the best percentage that is developing, proficient, exceeding, and emerging

5 0

3 years ago

Read 2 more answers

FREE BRAINLEIAST FOR FIRST GOGOGOGO!!

olga2289 [7]

Answer:

MEMEME

Explanation:

6 0

3 years ago

Mr. Ragusa asks Hassan to make silver crystals from the following reaction.

SVEN [57.7K]

Answer:

Percentage yield = 61.7%

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated:

2AgNO₃ + Cu —> Cu(NO₃)₂ + 2Ag

Next, we shall determine the mass of AgNO₃ that reacted and the mass of Ag produced from the balanced equation. This is illustrated below:

Molar mass of AgNO₃ = 108 + 14 + (16×3)

= 108 + 14 + 48

= 170 g/mol

Mass of AgNO₃ from the balanced equation = 2 × 170 = 340 g

Molar mass of Ag = 108 g/mol

Mass of Ag from the balanced equation = 2 × 108 = 216 g

SUMMARY:

From the balanced equation above,

340 g of AgNO₃ reacted to produce 216 g of Ag.

Next, we shall determine the theoretical yield of Ag. This can be obtained as follow:

From the balanced equation above,

340 g of AgNO₃ reacted to produce 216 g of Ag.

Therefore, 51 g of AgNO₃ will react to produce = (51 × 216)/340 = 32.4 g of Ag.

Thus, the theoretical yield of Ag is 32.4 g.

Finally, we shall determine the percentage yield of Ag. This can be obtained as follow:

Actual yield = 20 g

Theoretical yield = 32.4 g

Percentage yield =?

Percentage yield = Actual yield /Theoretical yield × 100

Percentage yield = 20 / 32.4 × 100

Percentage yield = 61.7%

6 0

3 years ago

What is the percent by mass of carbon in acetone, c 3 h 6 o?

Tatiana [17]

In the problem, we are tasked to solved for the amount of carbon (C) in the acetone having a molecular formula of C 3 H 6 O. We need to find first the molecular weight if Carbon (C), Hydrogen (H), Oxygen (O).

Molecular Weight:
C=12 g/mol
H=1 g/mol
O=16 g/mol

To calculate for the percent by mass of acetone, we assume 1 mol of acetone.
%C= $( \frac{3(12 g/mol)}{3(12 g/mol)+6(1 g/mol)+16 g/mol} ) x 100%$
%C=62.07%
Therefore, the percent by mass of carbon in acetone is 62.07%

5 0

3 years ago

Read 2 more answers

Why are the fruit and vegetable sections called the produce aisle?

QveST [7]

Fruits and vegetables are in the produce aisle because they are plants, and plants are producers.
Producers are organisms that create energy on their own through various processes depending on the organism.

6 0

3 years ago